if a+b<c or b+c<a or c+a
函数最终返回一个字典,包含三角形的类型和各角的余弦值。 python # 示例调用 result = pythontriangle(3, 4, 5) print(result) 运行上述代码,如果输入的三边能构成一个三角形,将输出类似以下结果: json { "type": "Right-angled triangle", "cos_A": 0.0, "cos_B": 0.6, "cos_C": 0.8 } 这个...
现在,我们可以使用Triangle类来创建三角形对象,并且调用其属性和方法。 triangle=Triangle("red",5,7)print(triangle.get_color())# 输出:redprint(triangle.get_area())# 输出:17.5triangle.set_color("blue")print(triangle.get_color())# 输出:blue 1. 2. 3. 4. 5. 在上述代码中,我们首先创建了一个T...
[3,4], [6,5,7], [4,1,8,3] ])# ans = s.minimumTotal([[2]])print(ans)
In the above program first we will take the values of three sides and we will find semi-perimeter and store in variable s. Next step we will calculate area using the formula and print the values using the print function in python. ...
In this Python tutorial, I will explain how tofind the area of a triangle in Python. You may or may not remember the formula of a triangle from your childhood classes, but it still seems very interesting to find its area. However, computing the area of the triangle involves calculation, ...
[Leetcode][python]Triangle/三角形最小路径和 题目大意 参考:https://shenjie1993.gitbooks.io/leetcode-python/120%20Triangle.html将一个二维数组排列成金字塔的形状,找到一条从塔顶到塔底的路径,使路径上的所有点的和最小,从上一层到下一层只能挑相邻的两个点中的一个。 注意点: 最好将空间复杂度控制...
python ,判断三角形的类型总共有五组数据,每组数据是每一个三角形的三条边的变长,写一个程序,判断这五个三角形分别什么形状side1=side2=side3=5triangle1=side1,side2,side3side1=3side2=4side3=5triangle2=side1,side2,side3side1=3side2=4side3=5triangle3=side1,side2,side3side1=1side2=2side...
print str[0:n+1]triangle("CMPT")[b] without using string slicesdef triangle(str): i = len(str) s = "" for n in xrange(i): s = s + str[n] print striangle("CMPT")结果一 题目 python求助Triangle FunctionCreate a function triangle(s), which takes a string s as its argument and...
Learn to code solving problems and writing code with our hands-on Python course. Try Programiz PRO today. Tutorials Examples Courses Try Programiz PRO Python Examples Print Hello world! Add Two Numbers Find the Square Root Calculate the Area of a Triangle Solve Quadratic Equation Swap Two ...