Furthermore, we show that, for each $k$, there exists\n$n_0$, such that, whenever $n\\geqslant n_0$, any $(n+k-2)$-vertex tournament\ncontains a copy of every $n$-vertex oriented tree with at most $k$ leaves,\nconfirming a conjecture of Dross and Havet....
There is an embedding ϕ of A in T such that ϕ(r)=v1. Proof Let us describe a greedy procedure giving an embedding ϕ of A into T. For each node a of A, we fix an ordering Oa of the children of a. If a vertex vj of T Unavoidability of trees with few leaves For ...
Audiophile claims about the superior sound quality are tenuous(3) and, outside a few minority subcultures, almost all new music can now be bought in alternative formats (including digital). This leaves my preference attached solely to the ritual of the needle drop, a habit which connects me t...
Furthermore, we show that, for each $k$, there exists $n_0$, such that, whenever $n\\geqslant n_0$, any $(n+k-2)$-vertex tournament contains a copy of every $n$-vertex oriented tree with at most $k$ leaves, confirming a conjecture of Dross and Havet....
In particular, a tree with three leaves is (n + 5)-unavoidable, i.e. g(3) ≤ 5. By studying trees with few leaves, we then prove that f(n) ≤ 38/5n - 6.Frederic HavetDiscrete mathematicsF. Havet. Trees in tournament. J. of Discrete Mathematic 243(1-3) (2002), 121-134...
In particular, a tree with three leaves is ( n +5)-unavoidable, i.e. g (3)5. By studying trees with few leaves, we then prove that f(n) 38 5 n6 .doi:10.1016/S0012-365X(00)00463-5Frédéric HavetElsevier B.V.Discrete Mathematics...