classSolution{publicList<Integer>postorderTraversal(TreeNode root){ List<Integer> res =newArrayList<>();if(root ==null)returnres; helper(root, res);returnres; }publicvoidhelper(TreeNode root, List<Integer> res){if(root ==null)return;//先add再递归helper(root.left, res); helper(root.right...
代码: 1/**2* struct TreeNode {3* int val;4* struct TreeNode *left;5* struct TreeNode *right;6* };7*/89classSolution {10public:11/**12*13* @param root TreeNode类14* @return int整型vector15*/16vector<int> postorderTraversal(TreeNode*root) {17vector<int>res;18if(root == NULL)...
后序遍历 后序遍历按照左子树、右子树、根节点的顺序进行遍历。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 defpost_order_traversal(node):ifnode:post_order_traversal(node.left)post_order_traversal(node.right)print(node.data,end=" ")# 示例post_order_traversal(root) 实际应用 树的应用非常广泛...
val), printPreorder(root.left) printPreorder(root.right) # Driver code root = Node(1) root.left = Node(2) root.right = Node(3) root.left.left = Node(4) root.left.right = Node(5) print("Preorder traversal of binary tree is") printPreorder(root) print("\nInorder traversal of ...
= left; * this.right = right; * } * } */ class Solution { List<Integer> result = new LinkedList<>(); public List<Integer> postorderTraversal(TreeNode root) { traversal(root); return result; } private void traversal(TreeNode root) { if (root == null) { return; } traversal(root...
Tree Tranverse: Pre/In/Post/Level Order tranverse Preorder: 迭代写法: class Solution { public List<Integer> preorderTraversal(TreeNode root) { List<Integer> res = new ArrayList<>(); if(root == null) return res; //we need to check it is null or not...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: //非递归方法实现后序遍历 vector<int> postorderTraversal(TreeNode* root) { vector<int> res; if(root==NULL) return res; stack<TreeNode *> vis; ...
/** * 先序遍历 postorder traversal 先输出根节点,然后输出子节点 * Created by Ryan Miao on 9/24/17. */ public class PostorderTraversal { @Test public void testPostOrder() { String root = "/Users/ryan/workspace/learning/hexo-blog-src"; int stop = 3; ArrayList<String> ignores = Lists....
Pre-order traversal in a tree Previous Quiz Next In this traversal method, the root node is visited first, then the left subtree and finally the right subtree. We start from A, and following pre-order traversal, we first visit A itself and then move to its left subtree B. B is also...
first the left successor is visited in preorder, then the right),in-order(also calledsymmetric order), andpost-order. In post-order, the ancestor is seen only after the post-order traversal of the left subtree and then the right. In-order has the in-order traversal of the left subtree...