public static int getDiameter(BinaryTreeNode root) { if (root == null) return 0; int rootDiameter = getHeight(root.getLeft()) + getHeight(root.getRight()) + 1; int leftDiameter = getDiameter(root.getLeft()); int rightDiameter = getDiameter(root.getRight()); return Math.max(root...
struct node* right; //right child int ht; //height of the node } node; You only need to complete the function. Note: All the values in the tree will be distinct. Height of a Null node is -1 and the height of the leaf node is 0. Output Format Insert the new value into the tr...
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* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution { vector<vector<int>>ret;intgo(TreeNode *p)//return max height{if(!p)return0;inthl = ...
Problem discription: Given an array where elements are sorted in ascending order, convert it to a height balanced BST. Accepted Code: 1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), ...