01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第136题(顺位题号是590)。给定一个n-ary树,返回其节点值的后序遍历。例如,给定一个3-ary树: 1 / | \ 3 2 4 / \ 5 6 其后序遍历结果为:[5,6,3,2,4,1]。 注意:递归解决方案是微不足道的,你可以用迭代的方式做吗? 本次解题使用的开发...
通用算法见LeetCode Binary Tree Inorder Traversal 第二轮: Given a binary tree, return thepostordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[3,2,1]. Note: Recursive solution is trivial, could you do it iteratively? 还是用老方法: 1/*...
LeetCode: 107_Binary Tree Level Order Traversal II | 二叉树自底向上的层次遍历 | Easy 编程算法 本题和上题一样同属于层次遍历,不同的是本题从底层往上遍历,如下:代码如下: 1 struct TreeNode { 2 int val; 3 TreeNo Linux云计算网络 2018/01/11 5060 LeetCode: 102_Binary Tree Level Order Traver...
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript 代码运行次数:0 运行 AI代码解释 3/\920/\157 return its level order traversal as: 代码...
Can you solve this real interview question? Binary Tree Level Order Traversal - Given the root of a binary tree, return the level order traversal of its nodes' values. (i.e., from left to right, level by level). Example 1: [https://assets.leetcode.c
It's essential to be mindful of boundary conditions when invoking the recursive function. 3. Code: Lists as parameters Indices as parameters High efficiency indices as parameters 3.1. Explaination of the Code: 3.1.1 Lists as parameters: Start by defining the function buildTree that takes the...
3 / \ 9 20 / \ 15 7 1. 2. 3. 4. 5. return its zigzag level order traversal as: AI检测代码解析 [ [3], [20,9], [15,7] ] 在102的基础上稍加改动即可 1. 2. 3. 4. 5. 6. 7. 8. AI检测代码解析 class Solution { ...
return its zigzag level order traversal as: [ [3], [20,9], [15,7] ] 1. 2. 3. 4. 5. 题目的意思非常直白。层序遍历整个树,可是第一层正序输出。第二层反序输出,第三层正序输出,以此类推。做法有两种:一、仍然採用level-travel,仅仅是引入一个标记,推断是否反转得到的数列; 二、考虑到stack的特...
** Inorder Traversal: left -> root -> right ** Preoder Traversal: root -> left -> right ** Postoder Traveral: left -> right -> root 记忆方式:order的名字指的是root在什么位置。left,right的相对位置是固定的。 图片来源:https://leetcode.com/articles/binary-tree-right-side-view/ ...
名字叫做, morrois traversal, 自己写了下: My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicList<Integer>inorderTraversal(TreeNoderoot){List...