Given a binary tree, return thelevel ordertraversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree[3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 return its level order traversal as: [ [3], [9,20], [15,7] ] 算法分析:三...
Map<Integer, List<Integer>> map = new HashMap(); public List<List<Integer>> verticalTraversal(TreeNode root) { List<List<Integer>> res = new ArrayList(); if(root==null) return res; // 借助了队列qt和qi,代替了递归 //树的所有节点 Queue<TreeNode> qt = new LinkedList(); // 节点坐标...
Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its zigzag level order travers...
*/classSolution{public List<Integer>preorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){if(current.left==null){result.add(current.val);current=current.right;}else{// has left, then find the rightmost of left su...
# Driver coderoot=Node(1)root.left=Node(2)root.right=Node(3)root.left.left=Node(4)root.left.right=Node(5)print("Preorder traversal of binary tree is")printPreorder(root)print("\nInorder traversal of binary tree is")printInorder(root)print("\nPostorder traversal of binary tree is")...
Given a binary tree, return the inorder traversal of its nodes' values. 主要思路: 1.递归 保持左根右的顺序即可 代码: definorderTraversal(self,root):""" :type root: TreeNode :rtype: List[int] """ifroot==None:return[]left=self.inorderTraversal(root.left)right=self.inorderTraversal(root...
Given a binary tree, return thepreordertraversal of its nodes' values. Example: Input:[1,null,2,3]1 \ 2 / 3Output:[1,2,3] Follow up:Recursive solution is trivial, could you do it iteratively? 给定一个二叉树,返回它的前序遍历。
Binary Tree Preorder Traversal 题目链接 题目要求: Given a binary tree, return thepreordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 1. 2. 3. 4. 5. return[1,2,3]. Note: Recursive solution is trivial, could you do it iteratively?
Binary Tree Level Order Traversal Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example: Given binary tree [3,9,20,null,null,15,7], 代码语言:javascript ...
Binary Tree algorithms implemented in java javabinary-treedepth-first-searchbreath-first-searchinorder-traversalpreorder-traversalpostorder-traversal UpdatedMar 17, 2024 Java Arko98/Alogirthms Star5 Code Issues Pull requests A collection of some of the most frequently used Algorithms in C++ and Python...