http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion-and-without-stack/ http://www.geeksforgeeks.org/morris-traversal-for-preorder/ http://stackoverflow.com/questions/6478063/how-is-the-complexity-of-morris-traversal-on http://blog.csdn.net/wdq347/article/details/8853371 Data ...
Iterative Preorder Traversal - GeeksforGeekswww.geeksforgeeks.org/iterative-preorder-traversal/ Iterative Postorder Traversal | Set 2 (Using One Stack) - GeeksforGeekswww.geeksforgeeks.org/iterative-postorder-traversal-using-stack/ 这个postorder有点tricky,需要考虑比如最左下角的一个node,只有rig...
[GeeksForGeeks] Get postorder traversal sequence from given inorder and preorder traversal. Given Inorder and Preorder traversals of a binary tree, print Postorder traversal. Example: Input: Inorder traversal in[] = {4, 2, 5, 1, 3, 6} Preorder traversal pre[] = {1, 2, 4, 5, 3,...
http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion/ Anwway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassS...
Binary Tree Zigzag Level Order Traversal Given a binary tree, return thezigzag level ordertraversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between). For example: Given binary tree{3,9,20,#,#,15,7}, ...
Given preorder traversal of a binary search tree, construct the BST. For example, if the given traversal is {10, 5, 1, 7, 40, 50}, then the output should be root of following tree. 10 / \ 5 40 / \ \ 1 7 50 1. 2.
classSolution:defpreorderTraversal(self,root:TreeNode)->List[int]:ifroot==None:return[]return[root.val]+self.preorderTraversal(root.left)+self.preorderTraversal(root.right) Runtime: 32 ms, faster than 89.16% of Python3 online submissions for Binary Tree Preorder Traversal. ...
还是用GeeksforGeeks的例子来描述如何做中序遍历吧。 Inorder (Left, Root, Right) : 4 2 5 1 3 树的遍历大部分都是可以给出迭代和递归两种做法的,此题我也给出两种做法。两种做法的时间和空间复杂度一样,时间都是O(n),空间都是O(h)。 迭代 ...
http://www.geeksforgeeks.org/morris-traversal-for-preorder/ http://stackoverflow.com/questions/6478063/how-is-the-complexity-of-morris-traversal-on title: 线索二叉树(Morris Traversal) tags: [数据结构, 二叉树] author: Mingshan categories: [数据结构, 二叉树] ...
/* Make current as right child of its inorder predecessor */ if(pre->right == NULL) { pre->right = current; current = current->left; } /* Revert the changes made in if part to restore the original tree i.e., fix the right child of predecssor */ ...