a, b, c, d, e, f, g, h, i= range(9) G= [{b, c, d, e, f},#a{c, e},#b{d},#c{e},#d{f},#e{c, g, h},#f{f, h},#g{f, g}#h]print(list(iter_dfs(G,a)))#[0, 5, 7, 6, 2, 3, 4, 1] 通用性的图遍历函数 deftraverse(G,s,qtype=set()): S,Q...
dom ×2 python ×2 stl ×2 c ×1 depth-first-search ×1 dictionary ×1 directory-traversal ×1 directory-walk ×1 glob ×1 graph ×1 iterator ×1 language-agnostic ×1 list ×1 matrix ×1 next ×1 os.walk ×1 reference ×1 symlink ×1 symlink-traversal ×1 tree ×1 xml ×1«...
:type root: Node :rtype: List[List[int]] """res = [] que = collections.deque() que.append(root)whileque: level = [] size =len(que)for_inrange(size): node = que.popleft()ifnotnode:continuelevel.append(node.val)forchildinnode.children: que.append(child)iflevel: res.append(level)...
代码(Python3) # Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def inorderTraversal(self, root: Optional[TreeNode]) -> List[int]: # ans 用...
# print(type(root), type(curr_level)) # (<class 'precompiled.treenode.TreeNode'>, <type 'list'>) # print(curr_level) # 作为list,却并不能遍历整个树 while curr_level: level_list = [] next_level = [] for temp in curr_level: ...
Python3代码 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def levelOrder(self, root: TreeNode) -> List[List[int]]: # solution two: 递归 res = [] def helper(root, ...
Python Java C C++ # Tree traversal in Python class Node: def __init__(self, item): self.left = None self.right = None self.val = item def inorder(root): if root: # Traverse left inorder(root.left) # Traverse root print(str(root.val) + "->", end='') # Traverse right in...
# @lc app=leetcode.cn id=145 lang=python3 # # [145] 二叉树的后序遍历 # # Definition for a binary tree node. from typing import List class TreeNode: def __init__(self, val=0, left=None, right=None): self.val = val self.left: TreeNode = left ...
Traversal over Python's objects subtree and calculate the total size of the subtree in bytes (deep size). - liran-funaro/objsize
In this traversal method, the left subtree is visited first, then the root and later the right sub-tree. We should always remember that every node may represent a subtree itself. If a binary tree is traversed in-order, the output will produce sorted key values in an ascending order. We ...