点D和E分别位于△ABC的边AB和BC上,点K和M将线段DE分为三等分,直线BK和BM分别与边AC相交于点T和P.求证 :TP≤1/3AC . 相关知识点: 试题来源: 解析 B [证]因为DK =KB =ME, 则可设 S_(△DBK)=S_(△KBM)=S_(△MBE)=S_0 , E D M K ① A ∴(S_(△ABT))/(S_O)=(AB⋅BT)/(...
百度试题 结果1 题目D,E分别是△ABC的边AB,BC上的点,点K,M将DE三等分,直线BK,BM分别交AC边于T,P证明:TP≤1/3AC向量没有图 相关知识点: 试题来源: 解析 某三位数是各位数字之和的23倍 反馈 收藏
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摘要: A solderless electrical connector formed of a polyolefin is formed with the same integrity as with harder polymeric materials when used with a connecting member of ductile material having a clearance slot between the wire receiving grooves and when formed to force the supporting cap into ...