Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: * You may assume k is always valid, 1 ≤ k ≤ number of unique elements....
Given a non-empty array of integers, return thekmost frequent elements. 给定一个不为空的数字数组,返回出现频率最高的k个元素。 Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input:nums = [1], k = 1Output:[1] Note: You may assumekis always valid...
classSolution(object):deftopKFrequent(self, nums, k):"""Given a non-empty array of integers, return the k most frequent elements. heapq.nlargest(n, iterable[, key]) Return a list with the n largest elements from the dataset defined by iterable."""count=collections.Counter(nums)returnheapq...
heappop(heap)[1] for _ in range(k)] 代码(Go) func topKFrequent(nums []int, k int) []int { // 统计 nums 中每个数字出现的次数, // 时间复杂度为 O(n) ,空间复杂度为 O(n) numToCnt := make(map[int]int) for _, num := range nums { // num 如果不在 num_to_cnt 中,则...
Given a non-empty array of integers, return the k most frequent elements. For example, Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm’s time complexity must be better than O(n log...
347. Top K Frequent Elements 前 K 个高频元素,给定一个非空的整数数组,返回其中出现频率前 k 高的元素。 示例1:输入:nums=[1,1,1,2,2,3],k=2输出:[1,2]示例2:输入:nums=[1],k=1输出:[1] 提示:你可以假设给定的 k 总是合理的,且1≤k≤数组中不相同的元素的个数。你的算
Top K Frequent Element top k 频率的数字 定义一个新结构,按照结构中频率字段排序即可。这里用了map去纪律每个数字的频率,时间复杂度一样,空间复杂度更低。 另外重写了一下快速排序,也可以用堆排,基数排序,实际都差不多。 有人用快排的思想去选择前k个元素,时间复杂度有点高,做了很多重复工作。选择第k个大...
[leetcode]347. Top K Frequent Elements K个最常见元素 Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [ ... 最高频的K个单词 · Top K Frequent Words [抄题]: 给一个单词列表,求出这个列表中出现频次最高的K个单词. [思维问题]: 以为已...
https://leetcode.com/problems/top-k-frequent-elements/ 3种方法 https://leetcode.com/discuss/100713/3-ways-to-solve-this-problem 普通方法heap O(nlogn): classSolution{public:vector<int>topKFrequent(vector<int>&nums,intk){unordered_map<int,int>mp;for(auto&i:nums)mp[i]++;priority_queue<...
Many big data applications today require querying highly dynamic and large-scale data streams for top-k frequent items in the most recent window of any specified size at any time. This is a challenging problem. We show that our novel solution is not only accurate, but it also one to two ...