百度试题 结果1 题目Cau 3: Tinh tong tat cá cac nghiem nguyen duong cua phuong trinh sau:(5+√(21))^2+(5-√(21))^2≤2^x+log_25 .A A. 1 B. 2 C. 3 D. 4 相关知识点: 试题来源: 解析 A 反馈 收藏
BT 16 Tinh cac nguyen ham sau:b) I=∫(dx)/(x^2√(9-x^2))I=∫(dx)/(√((x^2+1)^3)) d) I=∫(dx)/(x^2√(25-x^2))I=∫(x^3)/(√(1+x^2))dx I=∫(√(1-x^2))/(x^4)dx I=∫(dx)/(√(x^2-1))
3.Cacdoanhnghiepxuatkhaulaodong. -Trubckhituvan,tuyendunglaodongtaidiaphuong,cacdoanhnghiep phaicungcapdayduthongtincacdonhangdaduocCueQuanlyLaodong NgoainubcthamdinhveSoLaodong-TB&XH. -CungcapdayduthongtindonhangXKLD,cackhoan.chiphichodonvi ...
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Vi du 2. Tinh cac ho nguyen ham sau :a) ∫1/(sinx)dx :b) ∫1/(sin6x)dx :c) ∫1/(sin^4xc
BT 18. Tinh cac nguyen ham sau:a) I=∫(x^2-1)/(x^2)⋅lnx⋅dx⋅b) I=∫cos√x⋅dx c) I=∫_(sin):√x⋅dx d) I=∫_0^1(8x^3-2x)⋅e^(x^2)⋅dx e) I=∫x^3x^(x^2)dx I=∫x^5⋅e^(x^3)⋅dx f)1=g) I=∫_0^(sinx)⋅sin2x⋅dx .I=...
BT 7. Tinh cac nguyen ham sau:) I=∫(cosxdx)/(1+sinx)b) I=∫((2sinx-3)cosx)/(2sinx+1)⋅dx .2sinx+1◆I=∫(3cosxdx)/((1-sinx)^2) •*d) I=∫(2cosxdx)/(3+2sinx)e) I=∫sin^2xcos^3xdx . 相关知识点:
Tinh cac tich phan hoac tim cac nguyen ham sau:6.I =(a0)1.I=dx36.1=∫(dx)/((x^2-a^2)√(x^2-a^2)(a0) xdx2.I=7.1=∫_a^2(√(x^2-a^2))/xdx 3.1=∫_0^(π/2)(√((1-x^2)^3)dx 8.I =x--a dx x24 I=∫_(√2)^2(dx)/(x√(x^2-1))9.I =dx10.1=...