MarkLogic Server 11.0 Product Documentationsql:timestampdiff sql:timestampdiff( $dateTimeType as xs:ID, $timestamp1 as xs:genericDateTimeArg, $timestamp2 as xs:genericDateTimeArg ) as xs:integer? Summary Returns the difference in dateTimeType field of two given timestamps. Parameters dateTimeTy...
1 row in set 如果您希望看到差值,只需要将unit参数从MONTH更改为DAY,如下所示: mysql> SELECT TIMESTAMPDIFF(DAY, ‘2010-01-01’, ‘2010-06-01’) result; +——–+ | result | +——–+ | 151 | +——–+ 1 row in set 以下语句返回两个DATETIME值(以分钟为单位)的差异值: mysql> SELECT ...
内置性能分析插件:可输出 Sql 语句以及其执行时间,建议开发测试时启用该功能,能快速揪出慢查询 内置全局拦截插件:提供全表 delete 、 update 操作智能分析阻断,也可自定义拦截规则,预防误操作 支持数据库 mysql 、 mariadb 、 oracle 、 db2 、 h2 、 hsql 、 sqlite 、 postgresql 、 sqlserver 达梦数据库 、 ...
select TIMESTAMPDIFF(DAY, '2015-04-20 00:00:00', '2015-04-20 23:59:59');# 只要不足24小时 为0天 select TIMESTAMPDIFF(DAY, '2015-04-20 10:00:00', '2015-04-21 10:59:59');# 只要不足24小时 为0天 不足1天或1小时1分钟忽略不计 #selectDATEDIFF('2015-04-21 00:00:00','2015...
1 row in set (0.00 sec) sql语句 时间相加 tableiduserIdnamestarttimeendtime1001张三2015-06-2516:05:592015-06-2516:09:592001张三2015-06-2111:05:592015-06-2113:12:593001张三2015-06-2413:05:592015-06-2415:09:594002李… table id userId name starttime endtime ...
The problem is, you do not use the SQL scalar function TIMESTAMPDIFF documented. According to the documentation, the scalar function TIMESTAMPDIFF has 2 parameters. The first one is an integer value representing the date/time in which you want to return the difference. The second parameter is...
For SQL Server refer here http://msdn.microsoft.com/en-US/library/ms189794(v=sql.90).aspx For Oracle refer here http://docs.oracle.com/html/A95915_01/sqfunc.htm#i1006893 Regards, Mani You must be a registered user to add a comment. If you've already registered, sign in. Otherwise...