tic-tac-toe（C代码）tic-tac-toe（C代码）#include #include #include #define random(x) (rand()%x)int isWin(char Bo[],char player){ if((Bo[0] == Bo[1] && Bo[1] == Bo[2] && Bo[2] == player) || (Bo[3] == Bo[4] && Bo[4] == Bo[5] && Bo[5] == player) || ...
是指在C语言编写的tic tac toe(井字棋)游戏中,通过随机算法实现计算机的随机移动。 tic tac toe是一种简单的策略游戏,也被称为井字棋。在游戏过程中,两名玩家轮流在3x3的棋盘上放置自己的标记(通常是X和O),目标是在水平、垂直或对角线上连成一条直线。 在C语言编写的tic tac toe游戏中,实现计算机的随机...
while((c = getchar()) != '\n' && c != EOF); scanf("%c",&number); //why:ASCII码表对应的数字差48~ row = ((int)number-48-1)/3; col = ((int)number-48-1)%3; //printf("%d.%d.%c.\n",row,col,game[row][col]); //printf("%c\n",number); }while( game[row][col]...
The meaning of TIC-TAC-TOE is a game in which two players alternately put Xs and Os in compartments of a figure formed by two vertical lines crossing two horizontal lines and each tries to get a row of three Xs or three Os before the opponent does.
你应该注意到,如果你使用支持C++11的编译器,你可以使用一个std::vector而不是C类型的数组。Visual Studio 2012不支持这么做,但在Visual Studio 2013中支持。 复制 std::vector<tictactoe_status>strategy_o={{2, 0, 0, 0, 1, 0, 0, 0, 0},{2, 2, 1, 0, 1, 0, 0, 0, 0},{2, 2, 1, ...
c++ tic tac toe非整型字符导致无限循环是指在C++编写的井字棋游戏中,当玩家输入非整型字符时,程序会陷入无限循环的情况。 井字棋是一种双人对弈的棋类游戏,通常在一个3x3的棋盘上进行。玩家轮流在空白位置上放置自己的棋子,目标是将自己的棋子连成一条直线(横、竖、斜线)。
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data = np.loadtxt("./Data/tic-tac-toe.csv", skiprows=1, delimiter=',', converters={0:lambda name: label[name.decode()], 1:lambda name: label[name.decode()], 2:lambda name: label[name.decode()], 3:lambda name: label[name.decode()], ...
Tic-Tac-Toe CodeABCD ruleaccessory nipplesacralacrolentiginousactinic keratosisalopeciaamelonoticangiokeratomaangiomaarborizing blood vesselsProvides information on the tic-tac-toe code game.doi:WO2011071291 A2Miller, MarvinBoys Life
C = [] for i in C1: for ii in C2: if ii not in i: C.append(i + ii) return C def combinations(self, C1, C2, bit): for null in range(bit): C1 = self.combination(C1, C2) return C1 def view(self, raw): #os.system('cls') ...