LeetCode OJ:Three Sum(三数之和) Given an arraySofnintegers, are there elementsa,b,cinSsuch thata+b+c= 0? Find all unique triplets in the array which gives the sum of zero. Note: Elements in a triplet (a,b,c) must be in non-descending order. (ie,a≤b≤c) The solution set mu...
sum=num[left]+num[right-1] 因为数组有有序的,所以只有 3 种情况: sum == target 直接满足 sum < target,left++ sum > target, right-- 实现 class Solution { public List<List<Integer>> threeSum(int[] nums) { Arrays.sort(nums); Set<List<Integer>> res = new HashSet<>(); final int ...
classSolution{publicList<List<Integer>>threeSum(int[]nums){Set<List<Integer>>res=newHashSet<>();finalintn=nums.length;for(inti=0;i<n;i++){for(intj=i+1;j<n;j++){for(intk=j+1;k<n;k++){if(nums[i]+nums[j]+nums[k]==0){List<Integer>list=Arrays.asList(nums[i],nums[j],...
https://leetcode.com/problems/greatest-sum-divisible-by-three/ https://leetcode.com/problems/greatest-sum-divisible-by-three/discuss/431077/JavaC%2B%2BPython-One-Pass-O(1)-space https://leetcode.com/problems/greatest-sum-divisible-by-three/discuss/431108/Java-O(N)-solution-Simple-Math-O(1...
LeetCode 1013. Partition Array Into Three Parts With Equal Sum (Java版; Easy) 题目描述 AI检测代码解析 Given an array A of integers, return true if and only if we can partition the array into three non-empty parts with equal sums. ...
LeetCode 301960 Jul 11, 2017 Editorial SolutionpandasApproach 1: Return the First n Rows Using nlargest()AlgorithmFor this problem, we can either identify the top earners first using DataFrame employee and then join the DataFrame department to get the department name, or join the...
1 Two Sum C++, Go Easy LeetCode Shell#TitleSolutionDifficulty 4 Tenth Line Bash Easy 3 Transpose File Bash Medium 2 Valid Phone Numbers Bash Easy 1 Word Frequency Bash MediumLintCode#TitleSolutionDifficulty 1 Search in a big sorted array Java Medium 2 Search Range in Binary Search Tree Java...
()-1);ans.remove(ans.size()-1);while(lo<hi&&nums[lo+1]==nums[lo++]);while(lo<hi&&nums[hi-1]==nums[hi--]);}}}作者:clthinking-2链接:https://leetcode-cn.com/problems/4sum/solution/java-4ms-ji-bai-liao-100-ke-kuo-zhan-zi-ksumzhi-he/来源:力扣(LeetCode) 著作权归作者所有...
每当一个员工使用一次他的员工卡,安保系统会记录下员工的名字和使用时间。如果一个员工在一小时时间内使用员工卡的次数大于等于三次,这个系统会自动发布一个 警告。 给你字符串数组 keyName 和keyTime ,其中 [keyName[i], keyTime[i]] 对应一个人的名字和他在 某一天 内使用员工卡的时间。 使用时间的格式...
1363. 形成三的最大倍数 - 给你一个整数数组 digits,你可以通过按 任意顺序 连接其中某些数字来形成 3 的倍数,请你返回所能得到的最大的 3 的倍数。 由于答案可能不在整数数据类型范围内,请以字符串形式返回答案。如果无法得到答案,请返回一个空字符串。返回的结果