LeetCode OJ:Three Sum(三数之和) Given an arraySofnintegers, are there elementsa,b,cinSsuch thata+b+c= 0? Find all unique triplets in the array which gives the sum of zero. Note: Elements in a triplet (a,b,c) must b
sum=num[left]+num[right-1] 因为数组有有序的,所以只有 3 种情况: sum == target 直接满足 sum < target,left++ sum > target, right-- 实现 class Solution { public List<List<Integer>> threeSum(int[] nums) { Arrays.sort(nums); Set<List<Integer>> res = new HashSet<>(); final int ...
classSolution{publicList<List<Integer>>threeSum(int[]nums){Set<List<Integer>>res=newHashSet<>();finalintn=nums.length;for(inti=0;i<n;i++){for(intj=i+1;j<n;j++){for(intk=j+1;k<n;k++){if(nums[i]+nums[j]+nums[k]==0){List<Integer>list=Arrays.asList(nums[i],nums[j],...
https://leetcode.com/problems/greatest-sum-divisible-by-three/ https://leetcode.com/problems/greatest-sum-divisible-by-three/discuss/431077/JavaC%2B%2BPython-One-Pass-O(1)-space https://leetcode.com/problems/greatest-sum-divisible-by-three/discuss/431108/Java-O(N)-solution-Simple-Math-O(1...
Question: https://aaronice.gitbooks.io/lintcode/content/graph_search/six_degrees.html My code: 设计一个 HashMap 用来存到当前结点,需要的 step 也有做法是,拿一个更大的类把 GraphNode 包起来,同时包含一个step成员变量。表明到这个结点需要的step。 Anyway, Good l...Leet...
LeetCode 1013. Partition Array Into Three Parts With Equal Sum (Java版; Easy) 题目描述 Given an array A of integers, return true if and only if we can partition the array into three non-empty parts with equal sums. Formally, we can partition the array if we can find indexes i+1 < ...
LeetCode 301960 Jul 11, 2017 Editorial SolutionpandasApproach 1: Return the First n Rows Using nlargest()AlgorithmFor this problem, we can either identify the top earners first using DataFrame employee and then join the DataFrame department to get the department name, or join the...
LeetCode——633. 平方数之和[Sum of Square Numbers][中等]——分析及代码[Java] 一、题目 二、分析及代码 1. 双指针 (1)思路 (2)代码 (3)结果 三、其他 一、题目 给定一个非负整数 c ,你要判断是否存在两个整数 a 和 b,使得 a^2 + b^2 = c 。 示例...Leet...
1 Two Sum C++, Go Easy LeetCode Shell#TitleSolutionDifficulty 4 Tenth Line Bash Easy 3 Transpose File Bash Medium 2 Valid Phone Numbers Bash Easy 1 Word Frequency Bash MediumLintCode#TitleSolutionDifficulty 1 Search in a big sorted array Java Medium 2 Search Range in Binary Search Tree Java...
size() - 1); while (lo < hi && nums[lo + 1] == nums[lo++]) ; while (lo < hi && nums[hi - 1] == nums[hi--]) ; } } } } 作者:clthinking-2 链接:https://leetcode-cn.com/problems/4sum/solution/java-4ms-ji-bai-liao-100-ke-kuo-zhan-zi-ksumzhi-he/ 来源:力扣(Leet...