3/Using the numbers 3, 5, and 7, you can form different three-digit numbers. (Digits can be repeated) 相关知识点: 试题来源: 解析 本题考查了乘法原理:做一件事,完成它需要分成n个步骤,做第一步有m1种不同的方法,做第二步有m2种不同的方法,…,做第n步有mn种不同的方法,那么完成这件事共有...
How many three-digit numbers are there that have the sum of their digits equal to 10?. 相关知识点: 试题来源: 解析 54.. When the hundred digit is 1:109,118,127,⋯,190,there are 10 numbers; when the hundred digit is 2:208,217,226,⋯,280, there are 9 numbers; when the ...
一个三位数，只能由0，1，2，3，4，5来组成，它必须是5的倍数，这个数中每个数字使用不能超过2次。这样的数有几个？必须是5的倍数，说明最后一位只能是0或5.第一位数可以是1-5中任意一个，第二位数可以是0-5中任意一个，第三位数是0或者5.概率是5 x 6 x 2 = 60 因为每个数不能用两...
From Three Numbers, Hundreds of Answers ; States Are Fast Adopting Three-Digit Numbers That Offer Everything from Traffic Reports to Bingo-Night Schedulesdoi:10.1007/11740698_8Pop quiz: What three-digit number would you call to report astolen car? To figure out why your......
ahow many different three-digit numbers can you write using the digits 9,1,and 0?each digit may be used only once, and the digit 0 may not be used in the hundreds place.label the numbers you write as even or odd 正在翻译,请等待...[translate]...
If the middle digit is the average of the first and last digits, twice the middle digit must be equal to the sum of the first and last digits. Doing some casework: If the middle digit is , possible numbers range from to . So there are numbers in this case. If the middle digit is...
How many different three-digit numbers can we make by using the digits 1, 2, and 3 without repeating digits? What is the sum of all these possible three-digit numbers?相关知识点: 试题来源: 解析 6; 1332. 3* 2* 1=6; the sum is(1+2+3)* 222=1332....
How many four-digit numbers can there be if repetition of numbers are allowed and if repetition of numbers are not allowed? Using only the digits 5, 6, 7, 8, how many different 3 digit numbers can be formed if no digit is repeated in a number?
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Three digit numbers in which the middle one is a perfect square are fo... 04:32 Differentiate the following functions with respect to x f(x)=sqrt(x)+... 01:52 If I1=int(-1)^1(tan^(-1)x+1/x)dx&I2=int(-1)^1(cot^(-1)x+cot^(-1)1/x)dx... 02:34 The number of di...