jsCopy to Clipboard const obj4 = { name: "obj4", getThis() { return this; }, }; const obj5 = { name: "obj5" }; obj5.getThis = obj4.getThis; console.log(obj5.getThis()); // { name: 'obj5', getThis: [Function: getThis] } 如果方法被访问的值是一个原始值,this 也将...
传递常量型'Sales_data'作为'double Sales_data::avg_price()'函数的'this'参数 这个主要是因为这个函数没有声明为不修改对象,因此编译默认认为该函数会修改对象,不允许常量型对象调用这个方法。如果该函数不修改对象,建议将该函数定义为const类型。
在getX()和getY()函数定义后加上const,即int getX() const,int getY() cosnt。
20. 我一开始在成员函数 fetchWeather(const QString &cityName) 后面加上了 const 关键字,而函数后面加上 const 关键字代表在该函数中不能修改成员变量,而该函数中就是需要对成员变量进行操作,所以违反了该规定,只要将 const 关键字去掉...
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test.cpp:15: error: passing ‘const testing’ as ‘this’ argument of ‘int testing::test()’ discards qualifiers this refers to the object the member function (testing::test) operates on, and in this case it is not const, because testing::test was not declared with const, and thus th...
Unlike other arguments in overloaded functions, no temporary objects are introduced and no conversions are attempted when trying to match thethispointer argument. When the– >member-selection operator is used to access a member function, thethispointer argument has a type of class-name* const. If...
One name resolution change is that inside such a member function, you are not allowed to explicitly or implicitly refer to this. Copy struct cat { std::string name; void print_name(this const cat& self) { std::cout << name; //invalid std::cout << this->name; //also invalid std:...
'use strict';const{ArgumentParser}=require('argparse'); Expected behavior: Actual behavior: I have reduced a problem with TypeScript to a simple example. When trying to run tsc, I get the following error message but tslib should be available. ...
Re: Error: passing `const state' as `this' argument of `void state::dumpStat e()' discards qualifiersNeo wrote:[color=blue] > This is my first post in C++ group, so please be nice to me. Thanks.[/color]We play nice with those who play nice with us. [color=blue]...