To calculate the acceleration due to gravity on the Moon, we can use the formula for gravitational acceleration:
Calculate the value of acceleration due to gravity on moon. Given mass of moon =7.4×1022 kg, radius of moon=1740 km. View Solution If ge is acceleration due to gravity on earth and gm is acceleration due to gravity on moon, then View Solution The mass of a body on the surface of...
Betaflight: This open-source firmware focuses on flight performance. It has the largest user base, which makes starting out easier due to the abundance of tutorials. It also means support is readily available when you encounter issues. Additionally, Betaflight supports the widest range of flight co...
Find the acceleration due to gravity on the Venus, on the Moon and on the Sun. View Solution Given that the mass of the earth is 81.5 times the mass of the moon and the diameter of the moon is 0.27 times that of the earth . Calculate the value of acceleration due to gravity at ...
At what depth from the surface of the earth, the acceleration due to gravity will be half the value of g on the surface of the earth ? View Solution At what height above the surface of the earth will the acceleration due to gravity be25%of its value on the surface of the earth ?
Find the effective value of acceleration due to gravity at a height of 32 km from sea level : (Re=6400km) A0.5gm/s2 B0.99gm/s2 C1.01gm/s2 D0.90gm/s2Submit What is the acceleration due to gravity at a height h ( = radius of the earth) from the surface of the earth ? ltbgt ...
Height from the surface of the Earh, h = 1600 km. Radius of the Earth, R = 6400 km. Acceleration due to gravity on the surface of the Earth g0=9.8ms−2 ∴ acceleration due to gravity at the given height, g=g0(1+hR)2=9.8(1+16006400)=9.8×1625=6.272ms−2 Show More...
Similar Questions Find the acceleration due to gravity at a distance of 20000 km from the centre of the earth. View Solution What will be the acceleration due to gravity at a distance of 3200 km below the surface of the earth ? (Take Re=6400 km) View SolutionKnowledge...
The erroer in the measurement of density is : View Solution In an experiment to determine the acceleration due to gravity g, the formula used for the time period of a periodic motion is T=2π√(7R−r5g. The values of Randr are measured to be (60±1)mmand(10±1)mm, repecti...
The maximum value of sin2θ occurs when 2θ=90∘ or θ=45∘. - Conclusion: This statement is TRUE. 4. At maximum height, the acceleration due to gravity is perpendicular to the velocity of the projectile. - At maximum height, the vertical component of the velocity becomes zero, ...