TheStandardNormalCurve标准正态曲线 Finite Mathematics: Chapter 7, Section 6 1/5 The Normal Distribution In this section we will see that the histogram (which was briefly mentioned in section 7.2) for a binomial random variable can be approximated by a region under a smooth curve called a ...
Example 1: Find the areas of the shaded region under the standard normal curve. -2.05 Example 2: Find the areas of the shaded region under the standard normal curve. -2.7 Example 3: Find the areas of the shaded region under the standard normal curve. ...
【解析】The area under the standard normal curve between z = -1.5 and = 1.25is shown.1.25From the Standard Normal Table, the area to the left of = 1.25 is 0.8944 andthe area to the left of : = -1.5 is 0.0668. So. the area between : = -1.5 and1.25 isArea = 0.8944 - 0.0668 ...
Interactive Graph of the Standard Normal CurveJeff Sauro
百度试题 结果1 题目Usingthestandardnormalcurve,thez-scorerepresentingthe10thpercentileis1.28.相关知识点: 试题来源: 解析 错 反馈 收藏
Determine the area under the standard normal curve that lies to the left of a) z = -1.22. b) z = -0.28. c) z = -0.66. d) z = -0.38. Determine the area under the standard normal curve that lies to the left of (a) z = -0.82, (b) z = 0.25, (c) z = ...
What are the properties of the standard normal curve? Standard Normal Curve: There is a very important normal distribution, so much so that it has a special name. It is called the standard normal distribution, it generates the standard normal curve and it is relevant to write its characteristi...
百度试题 题目Using the standard normal curve, the z-score representing the 10th percentile is 1.28.相关知识点: 试题来源: 解析 错 反馈 收藏
Furthermore, if the normal distribution under study is the standard one, the parameters are understood when writing the random variable with the letter z.Answer and Explanation: The area under the standard normal curve to the left of z = 1.5 is given by: P(z<1.5)=? We can use ...
Answer to: Determine the area under the standard normal curve that lies between Z = -0.94 and Z = 0. By signing up, you'll get thousands of...