Let s be the square root of 289 Therefore s= square root of 289 {eq}\begin{align*} {s^2} = 289\\ {s^2} - 289 = 0\\ \left( {{s^2} - {{17}^2}}...Become a member and unlock all Study Answers Start today. Try it now Create an account Ask a question Our ...
What is the square root of 288? The square root of 288 is 16.970. Why is√288 an irrational number? A number with decimal expansion as non-terminating and non-repeating is always an irrational number. So,√288 is an irrational number. ...
Thesquare rootof 256 is 16. Why is the Square Root of 256 a Rational Number? Upon prime factorizing 256 i.e. 28, we find that all the prime factors are in even power. This implies that the square root of 256 is a positive integer. Therefore, the square root of 256 is rational. I...
How do you find the square root of 36? How do you find the square root of 1,800? How do you find the square root 289? Explain the steps of how you find the square root of a number. If the square root of three times a number is 15, how do you find the number?
Find the square root of6251296. View Solution Find the square root of6251296. View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths DC Pandey Solutions for Physics ...
(BSD)106as the preferred distance metric. BSD is calculated as the square root of the sum of squared differences between the branch lengths of a given tree pair. It is preferred over the more widely used Robinson–Fould (RF) distance107because the latter often results in narrow value ...
View Solution Find the square root of the following numbers by factor method. 17424 View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths Cengage Solutions for Maths DC Pandey Solutions for Physics ...
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In the remainder of this paper we will primarily be concerned with the recovery of the refractive index distribution (\(n=\sqrt{\epsilon _{r}}\)) defined as the square root of the relative permittivity. Scattered field inverse problem A more general setting than the OCT inverse problem ...
A fast and stable method for computing the square root X of a given matrix A (X2 = A) is developed. The method is based on the Schur factorization A = QSQH and uses a fast recursion to compute the upper triangular square root of S. It is shown that if α = ∥X∥2/∥A∥ is...