Let S be the set of ordered triples (x,y,z) of real numbers for which log_(10)(x+y)=z and log_(10)(x^2+y^2)=z+1. There are real numbers a and b such that for all ordered triples (x,y,z) in S we have x^3+y^3=a⋅10^(3z)+b⋅10^(2z). What is the valu...
1【题目】Let s be the set of ordered triples (x,y,z)of real numbers for which log1o(x +y)=z andlog1o(x2+y2)=z+1.T here are real numbers a andb such that for all ordered triples (x,y,z)in s we havex3+y3=a·103+b.102z.What is the value ofa+b?()A.152B.292C....
网络释义 1. 实数集 常用数学英语词汇 ... 有理数集 the set of all rational numbers实数集the set of all real numbers元素 element ... www.lfpyzx.cn|基于32个网页
参考资料：http://amc.maa.org/mathclub/5-0,problems/H-problems/H-web,ia/2002web/ha02-24-ia.shtml
value of ((1★2)★3) is (英汉小词典:each pair每对;real numbers实数;define定义;operation运算;value值) A. B. C. 0 D. 试题答案 在线课程 C 分析:按题中所给的新定义的运算,代入数据即可得解. 解答:∵(a★b)=, ∴((1★2)★3)
结果一 题目 Find the number of ordered pairs of real numbers (a,b) such that (a+bi)2002=a−bi.( )A.1001B.1002C.2001D.2002E.2004 答案 E相关推荐 1Find the number of ordered pairs of real numbers (a,b) such that (a+bi)2002=a−bi.( )A.1001B.1002C.2001D.2002E.2004 ...
百度试题 结果1 题目【题目】 Find the number of ordered pairs of real numbers (a,b) such that (a+bi)2002=a-bi.() A.1001 B.1002 C.2001 D.2002 E.2004 相关知识点: 试题来源: 解析 【解析】 E 反馈 收藏
For each pair of real numbers a≠b,define the operation★as (a★b)=a+ba−b,then thevalue of ((1★2)★3) is( )(英汉小词典:each pair每对;real numbers实数;define定义;operation运算;value值)A.
An inequality is an operation that describes how one number can be compared to another. Explore symbols for less than and greater than, how to use inequalities, and the order of real numbers. Which is Bigger? When you were little, did your teacher ever ask your class to line up from ...
Different standard representations of the real numbers are compared. It turns out that the crucial differences are of topological nature and that most of the representations (e.g., the decimal representation) are not reasonable for topological reasons. In the second part some effective representations...