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if alpha and beta are the roots of the equation ax^(2)+bx+c=0 then the equation whose roots are (1)/(alpha+beta),(1)/(alpha)+(1)/(beta) is equal to View Solution Ifα,βare the roots of the equationx2−p(x+1)−c=0, then(α+1)(β+1)= ...
If x^(2) - (5m - 2)x + 4m^(2) + 10m + 25 is a perfect square then m = ... Text Solution The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are 02:24 The roots of the equation 2(a ^2 +b^2)x^2+2(a+b)x+1=0 are 04:45 For p, q in R, the roots of...
Find the roots of the given equation x^2+9x+2=0. Find all roots of the equation x^3 + 2x - 3 = 0, given that 1 is a root of this equation. If L, M are the two roots of the equation x^{2} - 21x + 4 = 0 then find \sqrt{L} + \sqrt{M}. Find the roots of the ...
If the sum of the roots of the equation x 2 + kx - 3 = 0 is equal to the product of the roots, the value of k is? Solving second order equations Given a generic second-order equation, {eq}ax^2+bx+c=0 {/eq}, its roots can...
百度试题 结果1 题目 8. Let p be a solution of the equation x-2=0. Then the value of (p-1)(p^(12)+p^(13)+⋯+p^(41)) s A (A)124(B)144(C)192(D)212(E)252 相关知识点: 试题来源: 解析 答案见上 反馈 收藏 ...
Co-author of the study Jeff Temple said the phenomenon was "not terribly surprising" considering teens' interest in sexuality grows as they grow older, according to CNN. Of the 39 researches, 22 were from theUnited States, 12 from Europe and the rest from Australia, Canada, South Africa and...
The purpose of the present paper is to use the improvement of Runge's theorem on diophantine equations due to Schinzel to prove that if P has at least three different roots then the equation in the title has a finite number of solutions....
The periodic solution of the equation x ¨+f(x,x ˙)x ˙+g(x)=p(t) 来自 ResearchGate 喜欢 0 阅读量: 41 作者: N Shi 摘要: Using the method of averaging, the system of forced impact oscillator has been investigated. Periodic solution of the system considered and first approximation...
If the roots of x2+mx+n=0 are 2a and 2b and the roots of x2+px+m=0 are a and b, then using Vieta's equations, 2a+2b=−ma+b=−p2a(2b)=na(b)=m Therefore, substituting the second equation into the first equation gives m=2(p) and substituting the fourth equation into th...