(i)x²-3x-10=x²-5x+2x-10=x(x-5)+2(x-5)=(x-5)(x+2)Roots of this equation are the values for which(x–5)(x+2)= 0:x-5=0 or x+2=0i.e.,x=5 or x=-2(ii)2x²+x-6=2x²+4x-3x-6=2x(x+2)-3(x+2)=(x+2)(2x-3)Roots of this equation are the value...
Let λ≠ 0 be in ℝ. If α and β are the roots of the equation x2 x+2λ =0, and α and γ are the roots of the equation 3x2 10x+27λ =0, then βγλ is equal to
Find all roots of the equation x^3 + 2x - 3 = 0, given that 1 is a root of this equation. If L, M are the two roots of the equation x^{2} - 21x + 4 = 0 then find \sqrt{L} + \sqrt{M}. Find the roots of the following equation: (x 7)^2 = (x+3)^2 . Find th...
2 ∣∣ + ( − 4 ) + 2 = 0 , (x>0) View Solution Solve the equation:√3x2−√2x+3√3=0 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...
If the sum of the roots of the equation x 2 + kx - 3 = 0 is equal to the product of the roots, the value of k is? Solving second order equations Given a generic second-order equation, {eq}ax^2+bx+c=0 {/eq}, its roots can...
Find the roots of the equations. Q. (x^(2)+8)/(11)=5x-x^(2)-5 03:09 Find the roots of the equations. Q. (2x)/(x-4)+(2x-5)/(x-3)=8(1)/(2)... 05:56 The number of real solutions of the equation |x^(2)|-3|x|+2=0 is (a) 3... 02:13Exams...
Roots of the equation f (z)=α f (α) for the class of typically-real functionsLet T r be the class of functions f (z)=z+c 2 z 2 +..., regular in the disk ¦z¦ 0 in the remainder of the disk ¦z¦ <1. Let z f be the solution of f (z)= α f (a) on ...
(ii)Find all the roots of the equation z^(10)+z^5+1=0 ,giving each root in the form eie.[5] 相关知识点: 试题来源: 解析 3(ii) z^5=-1/2+i(√3)/2 z^5=erp(i2π(1/3+k)(i2π(-1/3+k)) exp(±t(2π)/(15),exp(t+(4π)/(15))⋅exp(t+(2π)/3),exp...
Use the quadratic formula to find the roots of the equation. 3x^2 - 4x - 8 = 0 Solve 3x^2 - 4 = 0 Solve: x^3 + 3x^2 = 2x + 6. Solve for x: 3x^2 - 12x + 3 = 0 Solve 3x^2 - 5x - 2 Solve for x ...
are the two roots of the equation 3 x − 6 x 2 = y in this domain. we obtain two disjoint intervals where \(\mathrm {d}_{\mathcal {a}}(f)\) might be: $$ \mathrm{d}_{\mathcal{a}}(f) \in \left[{\mathrm{u}\mathrm{p}\mathrm{p}\mathrm{e}\mathrm{r}_{2}}^{-...