Which of the following is the product of 2 consecutive integers?( ) A.182 B.195 C.208 D.221相关知识点: 试题来源: 解析 A 本题题意为“以下哪个是连续2个整数的乘积?”, A选项:182=13×14; B选项:195=13×15; C选项:208=13×16. 因此只有A选项是连续两个整数相乘. 故选A....
The product of two consecutive positive integers CANNOT be A. a prime number B. divisible by 11 C. a multiple of 13 D. an E. ven number less than 10E.a number having 4 as its units digit 答案：E 分析：正确答案:E 解析:两个连续正整数的积不能是:解:本题的正确答案是(E)。解决这类...
3. (Spring 2008 Junior A-Level Problem 1)An integer N is the product of two consecutive integers.(a) Prove that we can add two digits to the right of this number and obtain a perfect square.(b) Prove that this can be done in only one way if$$ N > $$ ...
Answer to: The product of two consecutive integers is 19 more than their sum. Find the integers. By signing up, you'll get thousands of...
The product of two consecutive positive integers is 306. Form the quadratic equation to find the integers, ifxdenotes the smaller integer. View Solution Exams IIT JEE NEET UP Board Bihar Board CBSE Free Textbook Solutions KC Sinha Solutions for Maths ...
A. −1 B. 0 C. 1 D. 1989 相关知识点: 试题来源: 解析 B The sum of two consecutive integers is always an odd number. 下列哪一个不能表示为两个连续整数的和( )? A.−1 B.0 C.1 D.1989 两个连续正数的和等于一个奇数. 故选B.反馈 收藏 ...
Theproductoftwoormoreconsecutivepositiveintegersis neverapower. Infactweshallproveastrongerresult: THEOREM2. Letk,1,nbeintegerssuchthatk >_3,1>_2andn+k>_p(k), wherep(k)istheleastprimesatisfyingp(k) >_k.Thenthereisaprimep>_kfor whichap#0(mod ...
The sum of two consecutive integers is 25. What are the two integers? A. 12 and 13 B. 11 and 14 C. 10 and 15 D. 13 and 12 相关知识点: 试题来源: 解析 A。解析:设较小的整数为 x,则另一个为 x + 1,x + x + 1 = 25,解得 x = 12,另一个数是 13。B 选项 11 和 14 ...
which of the following CANNOT be expressed as the product of exactly 2 consecutive integers?A:(2)(3)(7)B:(2)(3)(7)(11)C:(3的平方)(11)(13)D:(2)(5的平方)(13)E:(2的平方)(3)(5)(7)题目就是这样,由于我不会打平方,所以用文字表示.答案是选C, 扫码下载作业帮搜索答疑一搜即得 ...
The sum of two consecutive integers is between 5 and 9. What are the two integers?Inequality and consecutive integersThe solution to this problem can be derived from an inequality relation. Note that the boundary values are not included as possible solutions. Check the sol...