Python3, not the most clever solution. I just check if there's a pattern in G starting at index (i,j). defis_grid(G,P,g_i,g_j):p_m,p_n=len(P[0]),len(P)g_m,g_n=len(G[0]),len(G)if(g_i+p_n>g_n)or(g_j+p_m>g_m):returnFalseforiinrange(p_n):forjinrange...
Hackerrank果然是给hacker玩的,我这水平在上面真是举步维艰。 不过,这么搞下来,倒是有了实实在在的收获,如果学习算法能一直保持这种节奏就好了。 下面是AC的代码,时空复杂度均为O(N ^ 2): 1#2D Rabin-Karp Algorithm2importre34MOD = 10 ** 9 + 756defget2DMatrix(n, m):7a = [[0forjinxrange(m)...
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https://github.com/go-python/gopy https://github.com/chubaofs/chubaofs https://github.com/99designs/gqlgen https://github.com/luraproject/lura https://github.com/nanmu42/orly | 生成你自己的O'RLY动物书封面| 359 https://github.com/goburrow/quic https://github.com/megaease/easegress https...
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They want to know you can hack together an elegant and scalable solution using any language of choice. Knowing PHP is not especially important, particularly given that Facebook also does a lot of backend work in C++, Python, Erlang, and other languages. ...
Python 3 (using regex) defgridSearch(G,P):string="".join(G)separation=C-cifseparation<0:return"NO"pattern=fr'.{{{separation}}}'.join(P)formatchinre.finditer(pattern,string):rows=(match.end()-1)//C - match.start()//C + 1ifrows==r:return"YES"return"NO"...
Python Java C++ However, the core logic remains the same, and hence, these solutions can be translated into any other programming language. Contributing Pull requests are welcome. For major changes, please open an issue first to discuss what you would like to change. Please make sure to update...
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my code in javascript functiongridSearch(G,P){// Write your code hereconstn=G.length;constm=P.length;for(leti=0;i<=n-m;i++){// loop rowfor(letj=0;j<=G[i].length-P[0].length;j++){// loop Pletcheck=true;for(letk=0;k<m;k++){if(G[i+k].substring(j,P[0].length+j...