warning: the `gets' function is dangerous and should not be used. 原因:Linux 下gcc编译器不支持gets()这个函数,解决办法是使用 fgets fgets()函数的基本用法为: fgets(char * s,int size,FILE * stream); //eg:可以用fgets(tempstr,10,stdin) //tempstr 为char[]变量,10为要输入的字符串长度,stdin...
函数报错:warning: the 'gets' function is dangerous and should not be used. 随便百度一下都能出现很多解决问题,都是让你换成fput(),换了之后那还是解决问题吗?如: 解决办法:采用 fgets(str,100,stdin);//100为size 问题解决! 问题是解决了,警告没有了,没有了正常好吗?你把函数给我换了,我gets()函...
gets()方法在linux下使用gcc编译时会出现下列问题: warning: the `gets' function is dangerous and should not be used. 解决办法是使用 fgets()。 #include <stdio.h> #include <string.h> int main(){ char s[80]; //fgets()函数的基本用法为: //fgets(char * s,int size,FILE * stream); fget...
The basic problem is that the function doesn't know how big the buffer is, so it continues reading until it finds a newline or encounters EOF, and may overflow the bounds of the buffer it was given. You should forget you ever heard that gets() existed. The C11 standard ISO/IEC 9899:...
a2.c:6:5: warning: implicit declaration of function ‘gets’ [-Wimplicit-function-declaration] gets(a); ^ /tmp/cceyMQ7u.o: In function `main': a2.c:(.text+0x41): warning: the `gets' function is dangerous and should not be used. ...
warning: the `gets' function is dangerous and should not be used.,gets(buf)在linux下用gcc编译出现警告可以改为fgets(buf,MAX_PATH,stdin);//stdin意思是键盘输入同理:fputs(name,stdout);//stdout输出
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[-Wimplicit-function-declaration] 6 | gets(a); | ^~~~ | fgets ../Playground/: /tmp/ccI0Ulhr.o: in function `main': file0.c:(.text+0x15): warning: the `gets' function is dangerous and should not be used. What I understood through this example...
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