A. a number B. an equation C. a formula D. a combination of numbers and variables using algebraic operations 相关知识点: 试题来源: 解析 D。“algebraic expression”是指用代数运算把数字和变量组合起来。选项 A 是“一个数字”。选项 B 是“一个方程”。选项 C 是“一个公式”。反馈...
A. an equation of degree one B. an equation of degree two C. an equation of degree three D. an E. quation of degree F. our 相关知识点: 试题来源: 解析 B。“quadratic equation”是指二次方程。选项 A 是“一次方程”。选项 C 是“三次方程”。选项 D 是“四次方程”。反馈...
egalite,egality- social and political equality; "egality represents an extreme leveling of society" tie- equality of score in a contest 3.equation- the act of regarding as equal equating equalisation,equalization,leveling- the act of making equal or uniform ...
A、“formula”, or an “expression” was not necessarily an “equation”; 答案:答案:The word "expression" is inappropriate in the sentence. ... 点击查看完整答案手机看题 你可能感兴趣的试题 问答题 下行itbs取值范围 答案:答案:下行ITBS(Information Technology Baseline Security)取值范围通常指的是......
1.) Describe the relationship between input and output values for composite functions. 2.) Explain how you know if a radical expression is in the simplest form. 3.) How can you tell if radicals are Which of the functions are linear? Explain ...
C。解析:“3y - 5”是由数字、变量和运算符号组成的式子,这就是代数式(algebraic expression)。选项A,方程(equation)是含有等号的式子,这里没有等号。选项B,这不是函数的表示形式,函数要有输入输出的对应关系。选项D,这不是几何图形(geometric figure),几何图形是形状相关的概念。反馈...
On the left hand side of the equation, if the 3’s are cancelled, we would have (3*6*9)3=6*9=▱2. Therefore, the expression in the box should be 2*6*9 , since we can write 6*9=(2*6*9)2 Evaluating the left side of the expression, we obtain (3*6*9)3=54. Therefore...
Answer to: Write an expression that gives all the solutions to the equation \csc x - \sin x= \sqrt{2}. By signing up, you'll get thousands of...
Use Boolean Algebra to simply the equations: ABCD + AB (�C�D) + (�A�B)CD, ABC[AB + �C(BC + AC)] Which one of the following expressions represents the simplified Boolean function for F(A, B, C, D)? F(A, B, C, D) = A' B' C' D+ A' BC'...
This represents the length of the shortest program that prints the string x and then halts. Yet, as implied by Gödel’s incompleteness theorem or Turing’s halting theorem, we cannot compute the Kolmogorov complexity of an arbitrary string, given that it is impossible to test all possible al...