Calculus I: Lesson 6: Finding the Equation of a Tangent LineDr. Karen Brucks
In order to identify the equation of a tangent line to the function f(x) at a particular given point xo, we have to: Identify the derivative of the given function f′(x) Evaluate the derivative at the given point, f′(xo) Find the value of the function f(x)...
Answer to: Find the derivative at the given point and write the equation of the tangent line to the curve at the given point. f(x) = 2x^3+4x, a=4...
根据题意:The equation of the tangent line就是求此点的切线方程,先求过此点切线的斜率:求导得:y'=(1/3)(18 -2x)^(1/3-1)=(1/3)(18 -2x)^(-2/3)=1/[3³√(18 -2x)²]把x=5代入得:y'=1/[3³√(18 -10)²]=1/[3³√64]=1/[3·(4)]=1/12即切线斜率=1/12;y=...
equation of the line tangent 公式我们要找出直线与曲线相切的方程。 首先,我们需要知道切线的定义和性质,然后使用这些性质来找出切线的方程。 假设曲线方程为 y = f(x),切点为 (x0, f(x0))。 切线的斜率等于函数在该点的导数,即 f'(x0)。 所以,切线的方程可以表示为:y - f(x0) = f'(x0) ×...
What is an equation of the line tangent to the circle x⏫ + y⏫ = 32 at (4, 4)?A) y =
To solve the problem, we need to find the value of b for the ellipse given that the line tangent to the parabola y2=4x−20 at the point (6,2) is also a tangent to the ellipse defined by x22+y2b=1. 1. Identify the Equation of the Parabola: The given parabola is: y2=4x−...
The equation of a tangent line can be determined through various ways, and one of the key characteristics that we must consider is how a function is expressed. For one, when we are given an expression in polar coordinates, the slope of the...
Find the equation of line tangent to the graph of f(x)=e+ln x at x=1? 答案 e是常数,f'(x)=1/x,所以切线在x=1点的斜率是1,在x=1点的函数值是e.So the equation of the tangent line of graph at x=1 is f(x)=x+e-1相关推荐 1Find the equation of line tangent to the grap...
The slope of a function f(x) and the slope of the tangent line at the same point on f(x) are the same, and are equivalent to f′(a), where x=a is the point the tangent line and the function have in common. The equation of the tangent line can be obtaine...