1. **选项A(Iron,Fe)**:铁的原子序数为26,对应元素周期表中的第26位,与题目中的79不符。2. **选项B(Copper,Cu)**:铜的原子序数为29,用于导电材料,显然不是79。3. **选项C(Mercury,Hg)**:汞的原子序数为80,虽然接近79,但仍相差一位。4. **选项D(Gold,Au)**:金的原子序数明确为79,在元素周期表中...
In accordance with the criteria for the discovery of elements previously established by the 1992 IUPAC/IUPAP Transfermium Working Group (TWG), and reiterated by the 1999 and 2003 IUPAC/IUPAP JWPs, it was determined that the 1996 and 2002 claims by the Hofmann et al. research collaborations ...
The element with atomic number 14 is? A. Silicon B. Phosphorus C. Sulfur D. Chlorine 相关知识点: 试题来源: 解析 A。解析:原子序数为 14 的元素是硅元素。磷元素原子序数为 15,硫元素原子序数为 16,氯元素原子序数为 17。所以答案是 A。
To solve the question, we need to determine the outer shell electron configuration of the element with atomic number 118 and find which of the given atomic numbers (18, 28, 58, or 88) has the same outer shell configuration.1. Identify t
To determine the collective name for the elements with atomic numbers 10, 18, 36, 54, and 86, we can follow these steps:1. Identify the Elements: First, we need to identify the elements corresponding to the given atomic numbers
What is the abbreviation for sodium? A. Sa B. Sn C. So D. Na 相关知识点: 试题来源: 解析 D。钠元素的英文是 sodium,其缩写形式是 Na。选项 A“Sa”不是钠元素的正确缩写;选项 B“Sn”是锡元素的缩写;选项 C“So”不是钠元素的缩写。反馈 收藏 ...
Elements are the substances that make up all matter in the universe. Each element has a unique atomic number, which represents the number of protons inside the nucleus of one atom of that element. Protons are the positively charged particles inside an atom....
解析 首先句子后面是作定语的,由主句可以知道,修饰的是主语element.因为atoms是原子的意思,对于元素来说,逻辑关系自然是“元素里的原子”,所以element和atoms具有从属关系,用whose(注意啦!在定语从句表示从属关系的时候,关系词whose不仅仅适用于人,也可以适用于物)...
The element with atomic number 15 was found to be phosphorus 1531P (b) Interpretation Introduction Interpretation: From the given data, the corresponding elements and the number of each nucleons has to be found. Concept introduction: The smallest constituent of matter is...
The element X with mass number 4 and atomic number 2 is helium (He) .Ity has 2 electrons (maximum possible) in its only shell which is k shell .Therefore , the valency of the element is zero.