The atomic number indicates ___.A.the number of neutrons in a nucleusB.the total number of neutrons and protons in a nucleusC.the number of protons or electrons in a neutral atomD.the number of atoms in 1 g of an elementE.the number of different i
百度试题 结果1 题目The atomic number of an element represents the number of ___. A. protons B. neutrons C. electrons D. protons and neutrons 相关知识点: 试题来源: 解析 A。元素的原子序数代表质子数(protons)。反馈 收藏
A. The number of protons B. The number of neutrons C. The number of electrons D. The sum of protons and neutrons 相关知识点: 试题来源: 解析 A。原子序数由质子数决定。选项 A 正确,原子序数等于质子数。选项 B 中子数不能决定原子序数。选项 C 电子数在原子呈电中性时等于质子数,但不是决定原...
A. the number of protons in an atom B. the number of neutrons in an atom C. the number of electrons in an atom D. the total number of particles in an atom 相关知识点: 试题来源: 解析 A。元素的原子序数告诉我们一个原子中的质子数。原子序数等于质子数,选项 B 中子数不能由原子序数确...
The atomic number (原子序数) is equal to the number of electrons per atom or, what is equivalent, the number of protons (质子) per nucleus.相关知识点: 阅读 文言文阅读 文言题类 文言文阅读——翻译 试题来源: 解析 [答案]原子序数等于每个原子的电子数或者相当于每个原子核的质子数。反馈...
百度试题 结果1 题目What is the atomic number of an element?ps:Please answered in English 相关知识点: 试题来源: 解析 最佳答案译文,什么是元素的原子序数?It is the number of an element in thePeriodic table of the elements.反馈 收藏
The atomic number (原子序数) is equal to the number of electrons per atom or, what is equivalent, the number of protons (质子) per nucleus.正确答案 点击免费查看答案 试题上传试题纠错猜您对下面的试题感兴趣:点击查看更多与本题相关的试题同位素是() A. 原子序数相同,但质量数不同 B. 原子序数...
2. How many protons and electrons are found in an atom of nitrogen (atomic number 7)? 7 protons, 7 electrons 7 protons, 14 electrons 14 protons, 7 electrons 14 protons, 14 electrons Create your account to access this entire worksheet A Premium account gives you access to all lesson...
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together to form a heavier element. It's difficult to characterize these new elements because the super-heavy nuclei are unstable, readily decaying into lighter elements. Sometimes the new element itself isn't observed, but the decay scheme indicates the higher atomic number must have been formed...