解答解:(1)由题意得e=caca=√3232,2a2c=8√332a2c=833解得a=2,c=√33,b=1, 则椭圆方程x24x24+y2=1; (2)由B(0,1),C(0,-1),T(t,2), 则直线TB:y=1t1tx+1,代入椭圆方程可得xF=−8tt2+4xF=−8tt2+4,直线TC方程为:y=3tx−13tx−1, ...