The equation of the tangent line to the curve y = (18 -2x)^1/3 at the point where x = 5 is? 答案 y = (18 -2x)^1/3x=5,y=³√(18 -10)=2;根据题意:The equation of the tangent line就是求此点的切线方程,先求过此点切线的斜率:求导得:y'=(1/3)(18 -2x)^(1/3-1)=(...
The slope of the tangent line to the curve y = x³ at the point (1,1) is ___. A. 1 B. 2 C. 3 D. 4 相关知识点: 试题来源: 解析 C。解析:求 y = x³的导数,y' = 3x²,当 x = 1 时,斜率为 3,选项 C 正确。选项 A、B、D 都不符合。
100分求一道数学题,Find an equation for the tangent line to the curve x^2y + xy^3 = 2 at the point (1; 1). 答案 题目意思是,求曲线 x^2y + xy^3 = 2在点(1,1)处的切线方程.对方程两边取全导,d(x^2y)+d(xy^3)=2,2xydx+x^2dy+y^3dx+3xy^2dy=0,整理得 dy/dx=-(2xy+y^...
百度试题 结果1 题目The slope of the tangent line to the curve y = 2x^3 - 4x at x = 1 is: A. 2 B. 4 C. 6 D. 8 相关知识点: 试题来源: 解析 C。对函数求导得 y' = 6x^2 - 4,将 x = 1 代入得 y' = 6 - 4 = 2 。
Find an equation of the tangent line to the curve with parametric equationsx = t sin t,y = t cos t at the point (0,−π). 相关知识点: 试题来源: 解析 于提用了专谷歌但还难隆适找5参数方提-|||-X=t sint-|||-xt'sintt+tlos't=t(sinttlas't)-|||-fsi-|||-X何=1充(0-)...
Find an equation of the tangent line to the curve at the given point.y = sin 7x + sin2 7x,(0,0)y = sin(7x) + sin^2(7x),(0,0)求方程在(0,0)点的切线方程y= 答案 y'=7cos7x+14sin7xcos7xy'(0)=7切线为y=7x相关推荐 1Find an equation of the tangent line to the curve at...
百度试题 结果1 题目find an equation of the tangent line to the curve y=6xsinx at the point(π/2,3π)求y 相关知识点: 试题来源: 解析 求导y'=6(sinx+xcosx)在π/2处y'=6切线方程y-3π=6(x-π/2)即y=6x
百度试题 结果1 题目【题目】Find the slope of the tangent line to the curve 相关知识点: 试题来源: 解析 【解析】A(1,2),B(9,6)x_1=1 , y_1=2 , x_2=9 , y_2=6m=(y_2-y_1)/(x_2-x_1)=(6-2)/(9-1)=1/2 ∴m=1/2 ...
Thus, the tangent line is parallel to the vector (-1,1,-1) and parametric equations are x=1+(-1)t=1-t, y=0+1⋅ t=t, z=1+(-1)t=1-t.
Find the slope of the tangent line to the curve y=2√ (x-1) at the point P(5,4) 相关知识点: 试题来源: 解析 A(1,2) , B(9,6)x_1=1, y_1=2, x_2=9, y_2=6m= (y_2-y_1)(x_2-x_1)= (6-2)(9-1)= 1/2∴ m= 12...