If lim(x to 0) (x^n-sin^n x)/(x-sin^n x) is nonzero and finite , then ... 04:24 Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium
Learn what a tangent of a circle is by examining the definition, seeing an example of a tangent of a circle, and exploring the formula for calculating the equation of a tangent of a circle. Related to this Question 2. Prove lim_{x\to2}(-5x+3)=-7. ...
330°11π/6–1/√3= –√3/3 360°2π0 Inverse Tangent The inverse of the tangent function is thearctan function. Thus, if you know the tan of an angle, you can use arctan to find the measurement of the angle. Arctan can also be expressed as tan-1(x). ...
Integrate by parts using the formula ∫udv=uv−∫vdu∫udv=uv-∫vdu, where u=arctan(3x)u=arctan(3x) and dv=1dv=1. arctan(3x)x−∫x39x2+1dxarctan(3x)x-∫x39x2+1dxSimplify. Tap for more steps... arctan(3x)x−∫3x9x2+1dxarctan(3x)x-∫3x9x2+1dxSince...
Implicit Function Overview, Formula & Examples 4:30 Ch 2. Continuity Ch 3. Vectors in Calculus Ch 4. Geometry and Trigonometry Ch 5. How to Use a Scientific... Ch 6. Limits Ch 7. Rate of Change Ch 8. Calculating Derivatives and Derivative... Ch 9. Graphing Derivatives and L'Hopital...
1.Identify the integral: We need to compute∫xtan(x)dx. 2.Use integration by parts: We will use the integration by parts formula, which states: Here, we can let: -u=x(thusdu=dx) -dv=tan(x)dx 3.Findv: To findv, we need to integratetan(x): ...
Integrate ∫sec2xtan3xdx Integration by Substitution: The substitution rule is the integral analogue of the chain rule for derivatives. It says that ∫f(u(x))u′(x)dx=∫f(u)du for any functions f,u. Many integrals can be simplified by noticing that their integrands can be...
3 (i) Show that the equation tan(x-60°)+c0tx=√3 can be written in the form2tan^2x+(√
{eq}\displaystyle \int 8\tan^3 x \sec x \, dx {/eq} Take the constant out: {eq}= \displaystyle 8 \int \tan^3 x \sec x \, dx {/eq} {eq}=\displays... Learn more about this topic: Work Done Formula, Calculation & Examples ...
+x^5/5!-……（无穷级数形式）。类似地，对于cosx，其泰勒展开式为cos x = 1-x^2/2!+x^4/4!-……进一步，tanx的泰勒展开式可以表示为tanx=x+x^3/3+2x^5/15+17x^7/315+62x^9/2835++[2^(2n)*(2^(2n)-1)*B(2n-1)*x^(2n-1)]/(2n)!+。（|x|<π/2）