(tan2/x)=sec^2；2/x *（2/x）＝sec（2/x）*（-2/x）＝-2/x sec（2/x）导数（Derivative），也叫导函数值。如果函数f(x)在(a,b)中每一点处都可导，则称f(x)在(a,b)上可导，则可建立f(x)的导函数，简称导数，记为f'(x)如果f(x)在(a,b)内可导，且在区间端点a处的右...
Derivative $f’$ of the function $f(x)=\tan x$ is: \(\forall x \neq \frac{\pi}{2}+k\pi, k \in \mathbb{Z}, f'(x) = 1+\tan ^{2} x\) Proof First we have: \((\tan x)' =\lim _{h \rightarrow 0} \dfrac{\tan (x+h) - \tan x }{h}\) Now, let’s simplif...
tan^2x等于tanx-x,所以tanx-x的导数是tan^2x。如下所示: 导数(Derivative)是微积分中的重要基础概念。当自变量的增量趋于零时,因变量的增量与自变量的增量之商的极限。一个函数存在导数时,称这个函数可导或者可微分。可导的函数一定连续。不连续的函数一定不可导。导数实质上就是一个求极限的过程,导数的四则运算...
tan^2x等于tanx-x，所以tanx-x的导数是tan^2x。如下所示：导数（Derivative）是微积分中的重要基础概念。当自变量的增量趋于零时，因变量的增量与自变量的增量之商的极限。一个函数存在导数时，称这个函数可导或者可微分。可导的函数一定连续。不连续的函数一定不可导。导数实质上就是一个求极限的过程，...
Derivative of tangent function$g(x)=\tan x$ is: \(\forall x \neq \dfrac{\pi}{2}+k\pi, k \in \mathbb{Z}, \quad g'(x) = 1+\tan ^{2} x\) So, we have: \[\begin{aligned} f^{\prime}(x)&=\frac{1}{\tan^{\prime}(f(x))}\\ &=\frac{1}{1+\tan^2(f(x))}\...
Step 7: Final expressionUsing the identity 1+tan2x=sec2x, we have:f′(x)=2tanxsec2x Final AnswerThus, the derivative of tan2x is:f′(x)=2tanxsec2x --- Show More | ShareSave Class 11MATHSLIMITS AND DERIVATIVES Topper's Solved these Questions COMPLEX NUMBERSBOOK - RD SHARMA ENGLISHCHA...
dxd[tan2(4x)]=8sec2(4x)tan(4x) Explanation: Use the ... How do you take the derivative of tan2(5x) ? https://socratic.org/questions/how-do-you-take-the-derivative-of-tan-2-5x =10tan5xsec25x Explanation: Let t=5x . dxdtan25x=dxdtdtdtan2t ... How to Find the Derivatives...
0 0 0° 0.5 0.4636 26.565° 1/√3 π/6 30° 1 π/4 45° √3 π/3 60° 2 1.1071 63.435° 3 1.2490 71.565° ∞ π/2 90°See alsoTangent function Arccosine function Arcsine function Arctan of 0 Arctan of 1 Arctan of 2 Arctan of infinity Derivative of arctan Integral of arc...
(tan2/x)=sec^2；2/x *（2/x）＝sec（2/x）*（-2/x）＝-2/x sec（2/x）导数（Derivative），也叫导函数值。如果函数f(x)在(a,b)中每一点处都可导，则称f(x)在(a,b)上可导，则可建立f(x)的导函数，简称导数，记为f'(x)如果f(x)在(a,b)内可导，且在区间端点a处的右...
We know that the derivative of tan x is sec^2 x d/dx (tan x) = sec^2 x According to the chain rule, d/dx (tan 2x) = sec^2(2x) . d/dx (2x) Therefore, d/dx (tan 2x) = 2 sec^2 (2x)