If sec^4theta+sec^2theta=10+tan^4theta+tan^2theta", then "sin^2theta= 02:35 सिद्ध कीजिए की (1+ sin 2theta -cos 2theta ) /( 1+ sin 2theta + cos ... 03:06 Find the value of tan^2theta-sin^2theta-tan^2thetasin^2theta 02:24 Prove that...
सिद्ध कीजिए की (1+ sin 2theta -cos 2theta ) /( 1+ sin 2theta + cos ... 03:06 Find the value of tan^2theta-sin^2theta-tan^2thetasin^2theta 02:24 Prove that (1-tan^2theta)/(cot^2theta-1)=tan^2theta,thetane45^@ . 01:25 Prove that tan...
Prove the following trigonometric identities ( tan 2 theta sin 2 theta tan 2 theta sin 2 theta ) - To do:We have to prove that ( tan ^{2} theta-sin ^{2} theta=tan ^{2} theta sin ^{2} theta ).Solution:We know that,$tan theta=frac{sin t...
二倍角正切公式为tan2θ=2tanθ/(1-tan^2θ)。半角公式:半角公式是指将一个角的正弦、余弦或正切函数表示为另一个角的正弦、余弦或正切函数的公式。具体来说，设 $\theta$ 为一个角，则其正弦、余弦和正切的半角公式如下：\sin\frac{\theta}{2} = \pm\sqrt{\frac{1-\cos\theta}{2}} ...
化简(tan(theta)cos(theta))/(sin(theta)) tan(θ)cos(θ)sin(θ)tan(θ)cos(θ)sin(θ) 将tan(θ)tan(θ)重写为正弦和余弦形式。 sin(θ)cos(θ)cos(θ)sin(θ)sin(θ)cos(θ)cos(θ)sin(θ) sin(θ)cos(θ) cos(θ)cos sin(θ)cos(θ)cos(θ)sin(θ)sin(θ)cos(θ)cos(θ)sin...
Answer to: Prove the identity. sin^2(theta/2) = (tan theta - sin theta)/(2tan theta). By signing up, you'll get thousands of step-by-step solutions...
sin2(θ)+cos2(θ)=1 由于 ( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} )，我们可以将上述恒等式转换为涉及tan的形式：1+tan2(θ)=cos2(θ)1 因此，如果我们知道了tan的值，我们可以通过以下公式计算cos的值：cos(θ)=1+tan2(θ)1 同样，如果我们知道了cos的值，我们可以计算tan的...
已知\tan \theta = 2,则\sin ^{2}\theta + \sin \theta \cos \theta -2\cos ^{2}\theta = ___
∵tan\theta =2=\frac{sin\theta }{cos\theta } ∴sin\theta =2cos\theta tan^2\theta =\frac{1-cos^2\theta }{cos^2\theta }=\frac{1}{cos^2\theta }-1=4 ∴cos^2\theta =\frac{1}{tan^2\theta +1}=\frac{1}{5} ∴1+sin\theta cos\theta =1+2cos^2\theta =1+\frac{2}...
cos2(θ)⋅tan(θ)⋅sec(θ)cos2(θ)⋅tan(θ)⋅sec(θ) 将tan(θ)tan(θ)重写为正弦和余弦形式。 cos2(θ)⋅sin(θ)cos(θ)⋅sec(θ)cos2(θ)⋅sin(θ)cos(θ)⋅sec(θ) 约去cos(θ)cos(θ)的公因数。 点击获取更多步骤... ...