Given the following trigonometric identities (csc t) (sin t) cos t = 0.75 and tan t = 0.88 Find sec t and cot t; Verify the identity. \sin2t - \tan t = \tan t \cos 2t Show that the equation \cos t = \sqrt{1 - \sin^2 t} is not an identity. Prove that (cot^2 t...
Verify the identity. \dfrac{1-\sec(\theta)}{\tan(\theta)}-\dfrac{\tan(\theta)}{1-\sec(\theta)}=2\cot(\theta) Verify the trigonometric identity: 1 / {csc^2 x} + 1 / {sec^2 x} = 1. Verify the trigonometric identity: sin x (tan x + 1 / {tan x}...
三角函数计算器 输入> > > 有效位数>>> 三角函数计算器,可以方便地计算sin cosin tan cotan sec csc asin acos atan actan asen acsc的值,正弦 余弦 正切 余切 反正弦 反余弦 反正切 反余切计算器。
sec x - cos x = sin x tan x Prove the following identity: \dfrac{2 \: tan(\theta)}{1 + tan^2(\theta)} = sin(2\theta). Prove the following identity. sec x sin x = tan x. Prove the following identity. cos2x=cscxcosx/tanx+cotx Prove the following ide...
Answer to: Trig integrals. \int \tan^7(x) \sec^2(x) dx By signing up, you'll get thousands of step-by-step solutions to your homework questions...
2tanθ / (1 + tan2θ) = 2tanθ / sec2θ = 2(sinθ/cosθ) / (1/cos2θ) = 2(sinθ/cosθ) * cos2θ = 2sinθcosθ The identity is true. Upvote•2Downvote Add comment Report RECOMMENDED TUTORS Lisa O. 5.0(1,685) ...
(cosθ+isinθ)2−1(cosθ+isinθ)2+1(cosθ+isinθ)2−1(cosθ+isinθ)2+1 by cos2θcos2θ and then use the identity sec2θ=1+tan2sec2θ=1+tan2 on the result you obtain (1+itanθ)2−1−tan2θ(1+itanθ)2+1+tan2θ(1+i...
3. Convert the non-underlined terms in the result of part two into sec or tan depending on the rule you chose to use. What identity can we use to do this? 4. What relationships between sec and tan are we taking advantage of when we ...
Rewrite using trig identities:cos(120∘)sin(120∘) tan(120∘) Use the basic trigonometric identity: tan(x)=cos(x)sin(x)=cos(120∘)sin(120∘) =cos(120∘)sin(120∘) Use the following trivial identity:sin(120∘)=23 sin(120∘) sin(x) periodicity table with 360∘n cyc...
For this problem I would use sec2θ = 1 + tan2θ. The problem simplifies rather nicely in a few steps. If you need more help, let us know. In the future, to get you started, look for trig functions in the problem and see if there is a trig identity that has most (or all, ...