解:\tan\theta =3,则\cos 2\theta =\frac{\cos^2\theta -\sin^2\theta}{\cos^2\theta +\sin^2\theta }=\frac{1-tan^2\theta}{1+tan^2\theta } =\frac{1-9}{1+9} =-\frac{4}{5},所以C选项是正确的. 由条件利用角三角函数的基本关系,二倍角的余弦公式,求得\cos 2\theta 的值....
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若tan0=3 ,则 sin20= ___. 答案 [答案] 35 结果二 题目 4.若$$ \tan \theta = 3 $$,则sin2θ=___. 答案 【答案】$$ \frac { 3 } { 5 } $$ 【解析】 由正弦函数的倍角公式和三角函数的基本关系式, 得$$ \sin 2 \theta = 2 \sin \theta \cos \theta = \frac {...
\displaystyle 1+tan^{2}A=sec^{2}A \displaystyle 1+cot^{2}A=csc^{2}A How to Understand?(如何理解?) ↓↓↓ 下面给出正六边形帮助大家去理解三角函数之间的关系: 图3 三角函数6变形法则(来源:Baidu) 其图形特征为——上弦中切下为割,左正右余1中间。
【解析】 由已知可得$$ \cos 2 \theta = 2 \cos ^ { 2 } \theta - 1 $$ 又$$ \tan \theta = 3 $$ 则$$ t a n ^ { 2 } \theta = 9 $$ 又$$ 1 + \tan ^ { 2 } \theta = \frac { 1 } { \cos ^ { 2 } \theta } = 1 0 $$ 故$$ \cos ^ { 2 } \t...
यदि theta(1) , theta(2) , theta3 , ..., thetan समांतर श्रेणी में है जिसका सार्वअंतर d हैं, तो सिद्ध कीजि
If secxcos5x+1=0,w h e r e0<xlt=pi/2 , find the value of x . 03:10 If 3tan(theta-15^0)=tan(theta+15^0) 0<theta<90 then theta'= 07:04 Solve that following equations : "tantheta"+"tan"(theta+pi/3)+"tan"(t... 05:31 If tan ptheta- tan q theta = 0, then the...
结果1 结果2 题目3.若$$ \tan \theta = 3 $$,则$$ \frac { \sin \theta - 2 \cos \theta } { 3 \sin \theta + \cos \theta } $$的等于 ( ) A.$$ \frac { 1 } { 1 0 } $$ B.-$$ \frac { 4 } { 5 } $$ C.$$ \frac { 2 } { 5 } $$ D.-$$ \...
首先将 $2\tan\theta = -3\tan(\theta+\frac{\pi}{4})$ 转化为正切的差公式:2\tan\theta=-3\frac{\tan\theta+\tan\frac{\pi}{4}}{1-\tan\theta\tan\frac{\pi}{4}}化简得:-3\tan^2\theta+5\tan\theta+3=0解此方程,可得 $\tan\theta=-\frac{1}{3}$ 或 $\tan\...