First of all, you cannot write char str[]; without specifying the size Second, it's a terrible idea to scanf a string, use fgets Now let's see the meaning of & and why "strings" don't need it (this is not an easy subject, you should study it very carefully) ...
#include <bits/stdc++.h>#define ll long longusing namespace std;const int N = 1e5 + 5;int a ;int main() {int t;scanf("%d", &t);while (t--) {int n;scanf("%d", &n);vector<int> v;for (int i = 1; i <= n; i++) {cin >> a ;if (a & 1)//奇数v.push_back(i...
I walk through how you can construct a generic type that takes a snake_cased object ({foo_bar: string}) and produces the corresponding camelCased object ({fooBar: string}). This requires a bunch of concepts from TypeScript's type system: generic types, template literal types, conditional t...
We had variations of this problem at the 2014 and 2015 Greater NY Regionals. Input The first line of input contains a single integerP, (1 £P£ 1000), which is the number of data sets that follow. Each data set should be processed identically and independently. Each data set consists...
Sample Input 2: 4 5 0 1 1 0 2 2 2 1 3 1 3 4 3 2 5 Sample Output 2: Impossible 提交代码 AOV图。拓扑排序。 1#include<cstdio>2#include<algorithm>3#include<iostream>4#include<cstring>5#include<queue>6#include<vector>7#include<cmath>8#include<string>9usingnamespacestd;10intMap[10...
import java.util.Scanner; public class阶乘{ public static void main(string[] args){ Scanner m=new Scanner(System.in); System.out.printIn("请输入一个整数"); intn=m.nextInt(); int i=1,s=1; java求n的阶乘for循环 System i++