针对您遇到的“bad argument #1 to 'concat' (table expected, got string)”错误,这里我将分步骤地分析和解答您的问题,并提供可能的代码修正示例。 1. 确认错误来源 错误提示表明在调用Lua的concat函数时,第一个参数应该是table类型,但实际上传入的是string类型。这通常发生在尝试使用table.concat函数时,但错误地...
Expected behavior no error Actual behavior Error executing vim.schedule lua callback: ...te/pack/packer/start/null-ls.nvim/lua/null-ls/client.lua:39: bad argument #1 to 'unpack' (table expected, got string) stack traceback: [C]: in function 'unpack' ...te/pack/packer/start/null-ls...
2021/02/07 08:42:02 [error] 37#37: *11 failed to run body_filter_by_lua*: /etc/nginx/redis.lua:238: bad argument #1 to 'rawget' (table expected, got string) stack traceback: [C]: in function 'rawget' /etc/nginx/redis.lua:238: in function 'decode' /etc/nginx/ueditor/ueditor...
bad argument #2 to 'table' (number expected, got string) 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 原因在于,lua的table.insert 本来接收3个参数, table,pos,content 其中,pos可以省略,默认追加到table结尾 而我们gsub时候,实际上是返回了2个参数,所以insert时候被当作传入了3个参数,因此报错 因此...
版本:iview 1.5.1 table组件 添加了一行 row-key="id" 报错了: Invalid prop: type check failed for prop "rowKey". Expected Boolean, got String with value "id". 无效属性:属性“rowKey”的类型检查失败。应为布尔值,得到值为“id”的字符串。
8.Re: lua script - bad argument #1 to 'pairs' (table expected, got nil) Best Answer 1Recommend Garin Walsh Posted Mar 28, 2019 02:58 PM ReplyReply Privately So right now you have the code: if ( r_entry.probelist == nil ) then -- catch questionable data situation ...
table.remove将返回表中被删除的元素，而不是剩余的元素。
--失去焦点时更改"show"属性,显示文本--><el-inputref="saveTagInput"type="input"v-show="row.show"v-model="row[item.prop]"@blur="row.show = false"/></template><!--核心代码结束--></template></el-table-column></template></el-table></template><scriptlang="ts"setup>import { ref, ...
描述:lua: capi_study.lua:102: calling 'size' on bad self (luaBook.array expected, got userdata) 原因:void *ud = luaL_checkudata(L, 1, "LuaBook.array");中的"LuaBook.array"写成了"luaBook.array" 结果:Success! package.loadlib("array", "luaopen_array")() ...
E5108:Errorexecutinglua...te/pack/packer/start/null-ls.nvim/lua/null-ls/client.lua:39:badargument#1to'unpack'(tableexpected,gotstring) as you can clearly see,this linecomplaining aboutstring and table. That's whyunpackcausing error because it got string instead of table. ...