查阅内核代码,发现entry_SYSCALL_64_after_hwframe是从entry_SYSCALL_64开始执行的代码中的标号。因为从entry_SYSCALL_64到entry_SYSCALL_64_after_hwframe的过程中并没有类似于call这样的调用指令,这么说系统调用的入口是从netry_SYSCALL_64开始的。 继续用qemu打个断点看看,毕竟可以看到entry_SYSCALL_64_safe_stack...
* It's possible that a 32-bit syscall implementation * takes a 64-bit parameter but nonetheless assumes that * the high bits are zero. Make sure we zero-extend all * of the args. */regs->ax=ia32_sys_call_table[nr]((unsigned int)regs->bx,(unsigned int)regs->cx,(unsigned int)regs...
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curl 7.55.1 (x86_64-redhat-linux-gnu) libcurl/7.55.1 OpenSSL/1.1.0g zlib/1.2.11 libidn2/2.0.4 libpsl/0.18.0 (+libidn2/2.0.3) libssh2/1.8.0 nghttp2/1.25.0 Changes were made after 7.55.1 in ea142a8 to default to OpenSSL 1.1.0 default ciphers, Anyway, it is strange that Google...
查阅内核代码,发现entry_SYSCALL_64_after_hwframe是从entry_SYSCALL_64开始执行的代码中的标号。因为从entry_SYSCALL_64到entry_SYSCALL_64_after_hwframe的过程中并没有类似于call这样的调用指令,这么说系统调用的入口是从netry_SYSCALL_64开始的。 继续用qemu打个断点看看,毕竟可以看到entry_SYSCALL_64_safe_stack...
查阅内核代码,发现entry_SYSCALL_64_after_hwframe是从entry_SYSCALL_64开始执行的代码中的标号。因为从entry_SYSCALL_64到entry_SYSCALL_64_after_hwframe的过程中并没有类似于call这样的调用指令,这么说系统调用的入口是从netry_SYSCALL_64开始的。 继续用qemu打个断点看看,毕竟可以看到entry_SYSCALL_64_safe_stack...