今天用navcat往一个表添加外键的时候报错: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TYPE=InnoDB' at line 1 排查之后发现是因为两个表的类型不一样所致: SQL:SHOW TABLE STATUS 查询出数据表的状态,Engin...
SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL,ALLOW_INVALID_DATES'; CREATE SCHEMA IF NOT EXISTS `ProductDistribution_v9` DEFAULT CHARACTER SET latin1 ;...
CREATE TABLE account_profile ( accnt_id int NOT NULL , first_name varchar(255), last_name varchar(255), biography varchar(255), date_joined DATE, country varchar(255), gender varchar(255), screename varchar(255), path varchar(255), FOREIGN KEY (accnt_id) REFERENCES accounts(id) ) it...
建表的时候，最后一句最后面是不能加标点符号的，把它去掉就可以了。测试通过。
CREATE TABLE def (Sno CHAR(20),Gno CHAR(20),Cost FLOAT,PRIMARY KEY(Sno,Gno),FOREIGN KEY(Sno) REFERENCES Supplier(Sno),FOREIGN KEY(Gno) REFERENCES Goods(Gno))ENGINE=InnoDB DEFAULT CHARACTER SET=utf8 COLLATE=utf8_general_ci;表引擎需要是innodb才可以使用外键 ...
KEY `FK_gradeid` (`gradeid`), CONSTRAINT `FK_gradeid` FOREIGN KEY (`gradeid`) REFERENCES `grade` (`gradeid`) ) ENGINE=INNODB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci -- 方式一:创建表成功之后,添加外键约束 CREATE TABLE `student` ( ...
Error in SQL syntax manual that corresponds to your MySQL server version Create table Enroll(usn varchar(10),course_id varchar(10), attendance int(10),marks int(10,2),foreign key(usn) references bmsStudent(usn),foreign key(course_id) references Course(course_id)); Error1064(42000): you ...
CREATETABLEexample4(table_idINTPRIMARYKEY,first_nameVARCHAR(50)); MySQL CREATETABLEexample4(table_idINT(10)PRIMARYKEY,first_nameVARCHAR(50)); Postgres CREATETABLEexample4(table_idINTEGERPRIMARYKEY,first_nameVARCHAR(50)); Example 5 – Inline Primary Key and Foreign Key ...
NO ACTION, which is a standard SQL keyword, is the default in MySQL 9.0. (Also the same as with InnoDB.) In earlier versions of NDB Cluster, when creating a table with foreign key referencing an index in another table, it sometimes appeared possible to create the foreign key even if ...
CREATE TABLE Bewerbung ( BungID INTEGER NOT NULL AUTO_INCREMENT, Datum DATE, Punkte INTEGER, FsBeruf VARCHAR, PRIMARY KEY (BungID), FOREIGN KEY (FsBeruf) REFERENCES Beruf(BerufID) ); And this one: CREATE TABLE Bearbeiter ( BearbeiterID INTEGER NOT NULL AUTO_INCREMENT, ...