你的return的上一句后面少了分号，语法有错。
另外printf("a=%d,b=%d,c=%d,x=%d,y=%d,z=%d\n", a, b, c, x, y, z)结尾要加个分号，才能编译通过。请采纳，谢谢。
这段代码很简单,第一句先打印命令行参数个数,随后将各个参数逐行输出。 代码看似没什么问题,然后使用VC++6.0编译时却报了个syntax error : missing ‘;’ before 'type’的错误,并且定位在 int i = 0;这一行。 后来我将int i = 0;移动到了main函数的第一行,错误消失,编译成功。。。(what the fuck!) ...
error C2143: syntax error : missing ';' before (identifier) 'xxxx',编号:C2143直译:在(标志符)“xxxx”前缺少分号。错误分析:这是VC6的编译期最常见的误报,当出现这个错误时,往往所指的语句并没有错误,而是它的上一句语句发生了错误。其实,更合适的做法是编译
Error ID: BC30035To correct this errorExamine the documentation for each of the keywords used in the source code line. Compare the example code in the documentation against the source line generating this error. If you cannot identify the cause of the error, gather information about the ...
else(x<0),else后不允许带条件，去掉(x<0)即可
)/((a+b)*(c+d)*(a+c)*(b+d)); #define f(x) 这两段代码好像有问题，特别是下面那句，用来干嘛？建议使用传统的函数形式，你的这种函数形式容易出错。 有个严重错误：void main(){}和int main(){return 0;}格式搞混了，注意了，你的这两种格式混合使用了，肯定会错的。这个...
Usually means that there is an error or omission in the previous line(s). Check for a missing semi-colon or other error(s) in the line(s) immediately *before* the one indicated by the error message. Check also for a missing semi-colon at the end of class and structure definitions. ...
(/:after|/:before)?","__typename":"PageDescriptor"},"__typename":"PageResource"},{"lastUpdatedTime":1730819800000,"localOverride":null,"page":{"id":"AllEvents","type":"CUSTOM","urlPath":"/Events","__typename":"PageDescriptor"},"__typename":"PageResource"},{"lastUpdatedTime":...
cout<<"error"<<endl; return; } else { cout<<"该学生信息为:"<<endl; cout<<*i<<endl; }}void menu(){ cout<<"***"<<endl; cout<<"***学生信息管理***"<<endl; cout<<"***"<<endl; cout<<"**1.输入学生并显示学生信息 ***"<<endl; cout<<"**2.添加学生 ***"<<endl...