Axis of Symmetry fory=ax2+bx+cisx=−b2a a=1,b=0 x=−02·1 Refine x=0 Graph Plotting:y=x2 Sorry, your browser does not support this application View interactive graph Examples x2−x−6=0 −x+3>2x+1 line(1,2),(3,1) ...
( f(x)=2((10x))^2-1) 相关知识点: 试题来源: 解析 Set the polynomial equal to ( y) to find the properties of the parabola.( y=2((10x))^2-1)Rewrite the equation in vertex form.( y=200((x+0))^2-1)Use the vertex form, ( y=a((x-h))^2+k), to determine t...
How we do this depends on the type of symmetry:For Symmetry About Y-AxisFor symmetry with respect to the Y-Axis, check to see if the equation is the same when we replace x with −x:Example: is y = x2 symmetric about the y-axis? Try to replace x with −x: y = (−x)2...
Given the function f(x)= -7x^2 - 14x -3, find: (a) the vertex (b) the axis of symmetry How do you find the y-intercept, axis of symmetry, and the vertex to graph the function f(x) = -0.25x^2 + 5x? Identify the axis of symmetry and the vertex for the func...
( y=2x^2+6x-1) 相关知识点: 试题来源: 解析 Rewrite the equation in vertex form. ( y=2((x+3/2))^2-(11)/2) Use the vertex form, ( y=a((x-h))^2+k), to determine the values of ( a), ( h), and ( k). ( a=2) ( h=-3/2) ( k=-(11)/2) Since the val...
The symmetry of the 2P excitonic wave functions in strained ZnSe thin films is directly investigated for the first time in the time domain by using a coherent control technique with a phase-locked pulse pair. When the incident photon energy is two-photon resonant with the 2P exciton levels, ...
We can obtain the axis of symmetry of a quadratic function by finding the x-coordinate of the vertex, which uses the following formula:x=−b2aAnswer and Explanation: Given: y=3x2+6x+5 Our objective is to Identify the axis of symmetry of the parabola: First, we ...
y=(x+4)2+0 y=(x+4)2+0y=(x+4)2+0 Use thevertexform,y=a(x−h)2+ky=a(x-h)2+k, to determine the values ofaa,hh, andkk. a=1a=1 h=−4h=-4 k=0k=0 Since the value ofaais positive, theparabolaopens up.
x=−y2−0.1x=-y2-0.1 There are three types of symmetry: 1. X-Axis Symmetry 2. Y-Axis Symmetry 3. Origin SymmetryIf (x,y)(x,y) exists on the graph, then the graph is symmetric about the: 1. X-Axis if (x,−y)(x,-y) exists on the graph 2. Y-Axis if (−x,y)...
( x=-((y+0))^2+2) Use the vertex form, ( x=a((y-k))^2+h), to determine the values of ( a), ( h), and ( k). ( a=-1) ( h=2) ( k=0) Since the value of ( a) is negative, the parabola opens left. Opens Left Find the vertex( (h,k)). ( (2,0)) ...