Hi, I came across a task, how to use switch / case with range of numbers? for example: int count; switch(count) { case 0 ... 999 : cout << "First Case"; break; case 1000 ... 1999 : cout << "Second Case"; break; . . } I am not sure about syntax : if I want the ...
Flowchart of C++ switch...case statement Example: Create a Calculator using the switch Statement // Program to build a simple calculator using switch Statement#include<iostream>usingnamespacestd;intmain(){charoper;floatnum1, num2;cout<<"Enter an operator (+, -, *, /): ";cin>> oper;cout...
Flowchart of JavaScript switch statement Example 1: Simple Program Using switch...case Suppose we want to display a message based on the current day of the week. Let's look at the example below to see how we can achieve this usingswitch...case. ...
一、这题目不适合用switch语句，用if语句就可以了。二、switch语句不是你这样用的，switch（）括号中，需要一个整形的结果，case后面，必须是整形的常数，而且，case语句后，一般要有个break来保证，不会去执行其他的语句。详情，请多看一下书中的介绍。
e.g. 1 下面这段代码使用NSString指针作为switch参数,编译无法通过, 提示Statement requires expression of integer type(‘NSString *__strong‘ invalid)错误 NSLog(@"(NSInteger)str=%lx", (NSInteger)str); switch (str) { case (NSInteger)nil: ...
SWITCH vs. IF Let's revisit the measurement example using theSWITCHfunction this time. The first advantage is the number of formulas used in this argument. When creating a nestedIFstatement, you need to be actively tracing where you’re at in the formula at each step. Using theSWITCHformula...
switch (expression)statement labeled-statement: caseconstant-expression:statement default :statement Control passes to the statement whosecaseconstant-expressionmatches the value ofswitch (expression). Theswitchstatement can include any number ofcaseinstances, but no two case constants within the sameswitch...
Requirements Namespace:Microsoft.VisualBasic Module:Interaction Assembly:Visual Basic Runtime Library (in Microsoft.VisualBasic.dll) See Also Reference Choose Function IIf Function Select...Case Statement (Visual Basic) Concepts Parameter Arrays
switch{}你少了大括号
case 后面一般跟常量 每个case后面要加break 字符串要用双引号 所以这个题目不能用switch case完成 还是if else吧 include<iostream>using namespace std;int main(){ int x; cin>>x; if ((x%3==0)&&(x%5==0)&&(x%7==0)) cout<<"能同时被3,5,7整除"<<endl; else...