Monocarp has got two stringsss andtt having equal length. Both strings consist of lowercase Latin letters "a" and "b". Monocarp wants to make these two stringsss andtt equal to each other. He can do the following operation any number of times: choose an indexpos1pos1 in the stringss,...
Monocarp has got two strings ss and tt having equal length. Both strings consist of lowercase Latin letters "a" and "b". Monocarp wants to make these two strings ss and tt equal to each other. He can do the following operation any number of times: choose an index pos1pos1 in the st...
Codeforces 1215C. Swap Letters 传送门 好像是个挺显然的贪心 首先每次交换当然要尽量一次交换就多两个相同的位置 即 优先把[ab][ab]和[ab][ab]交换 优先把[ba][ba]和[ba][ba]交换 最后如果剩下[ab][ab],[ba][ba]各一个 我们才只好用两次交换次数把它们搞好,这样就是最优的了 当然如果最后某一种...
having equal length. Both strings consist of lowercase Latin letters "a" and "b". Monocarp wants to make these two strings s and t equal to each other. He can do the following operation any number of times: choose an index pos1 in the string s, choose an index pos2 in the string ...
Codeforces 1215C. Swap Letters #include 传送门 好像是个挺显然的贪心 首先每次交换当然要尽量一次交换就多两个相同的位置 即 优先把 $\begin{bmatrix}a\\ b\end{bmatrix}$ 和 $\begin{bmatrix}a\\ b\end{bmatrix}$ 交换 优先把 $\begin{bmatrix}b\\ a\end{bmatrix}$ 和 $\begin{bmatrix}b\...
Monocarp has got two strings s and t having equal length. Both strings consist of lowercase Latin letters "a" and "b". Monocarp wants to make these two strings s and t equal to each other. He can do the following operation any number of times: choose an index pos1 in the string s...
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S is a string of length between 2 and 10 6 , inclusive, consisting of lowercase English letters. Input The input is given from Standard Input in the following format: S Output Print the number of strings that can result from performing the operation in the problem statement exactly once on...
There is no known algorithm that solves the general case of the Approximate Edit Distance problem, where the edit operations are: insertion, deletion, mismatch, and swap, in time o(nm), where n is the length of the text and m is the length of the pattern
importjava.util.ArrayList;importjava.util.Collections;publicclassPerformSwap{publicstaticvoidmain(String[]args){ArrayList<String>lettersList=newArrayList<String>();lettersList.add("a");lettersList.add("b");lettersList.add("c");lettersList.add("d");lettersList.add("e");lettersList.add("f");...