给你k 枚相同的鸡蛋,并可以使用一栋从第 1 层到第 n 层共有 n 层楼的建筑。 已知存在楼层 f ,满足 0 <= f <= n ,任何从 高于 f 的楼层落下的鸡蛋都会碎,从 f 楼层或比它低的楼层落下的鸡蛋都不会破。 每次操作,你可以取一枚没有碎的鸡蛋并把它从任一楼层 x 扔下(满足 1 <= x <= n...
Can you solve this real interview question? Super Egg Drop - You are given k identical eggs and you have access to a building with n floors labeled from 1 to n. You know that there exists a floor f where 0 <= f <= n such that any egg dropped at a floor
Can you solve this real interview question? Find the Shortest Superstring - Given an array of strings words, return the smallest string that contains each string in words as a substring. If there are multiple valid strings of the smallest length, return
Github 同步地址: https://github.com/grandyang/leetcode/issues/887 参考资料: https://leetcode.com/problems/super-egg-drop/ https://www.cnblogs.com/Phantom01/p/9490508.html https://www.acwing.com/solution/leetcode/content/579/ https://leetcode.com/problems/super-egg-drop/discuss/159508/easy...
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661. ImageSmoother*https://leetcode.com/problems/image-smoother/题目描述Given a 2D integer matrix M representing the g leetcode 算法 2d c++ 原创 珍妮的选择 2022-05-30 10:51:16 68阅读 661. ImageSmoother Given a 2D integer matrix M representing the gray scale of an image, you need to ...
517 Super Washing Machines 超级洗衣机,详见:https://leetcode.com/problems/super-washing-machines/description/C++:classSolution{public:intfindMinMoves(vector<int>&machines){intsum=accumulate(machines.be
super IO -83627 datasheet 详细介绍了83627的资源! 83627IO 资料2009-11-23 上传大小:2.00MB 所需:10积分/C币立即下载 NCT6102D / NCT6106D Nuvoton LPC I/O NCT6102D NCT6106D Nuvoton LPC Date: January 11th, 2012 Revision 1.0,The NCT6102D / NCT6106D is a member of Nuvoton‟s Super I/O...
转码DS必备!跳槽大厂秘籍 🌟1. Coding算法 刚开始转行时,没有CS背景,从头开始学习数据结构和算法。当年在LeetCode上刷了200道easy和medium难度的题目。面试DS时,这些题目完全够用。经典题目如"Number of Islands"被考了三遍。建议做题时用Excel记录,按题号、难度、做题日期、数据结构算法类型、公司高频排序,这样可...
So, Q(k,s) = 1 + Q(k, s-1) + Q(k-1, s-1); dp[i] is max floors we can use i eggs and s step to detect. Reference: https://leetcode.com/problems/super-egg-drop/discuss/159508/easy-to-understand 永远渴望,大智若愚(stay hungry, stay foolish)...