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summation of geometric progression几何级数求和 geometric progressionn.[数]等比级数 in progression连续, 相继 hypergeometric progression超几何级数 backward progression【医】 后退 progression jet起动喷嘴 finite progression有限级数 double summation二重求和法 ...
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Geometric Progression sum formula (Sn) = a1 (rn -1)/ r-1 for r ≠ 1 Sum of Infinite Series Formula Sum of an infinite series formula for the geometric formula with the common ratio r satisfying |r| < 1 is given as: S∞ = \[\frac {a}{1-r}\] The notation for the above sum...
1.The summation formula of series sum from k=2 to ∞ f(k)■(k);级数sum from k=2 to ∞f(k)(非汉字符号)(k)的求和公式 2.Krattenthaler obtained a general matrix inversions which unified most matrix inversions, and it was applied to derive a number of summation formulas of hypergeometric...
This chapter discusses the prehistory of the zeta-function. For an infinite geometric progression, the "last number" is "nothing or a point"; it can be sai... ANDR WEIL - 《Number Theory Trace Formulas & Discrete Groups》 被引量: 30发表: 1989年 The correctness of Euler's method for th...
The latter problem was connected to the question of expressing the sum of a series using an integral. The outcome of this research was Euler's derivation of what would later become known as the Euler–Maclaurin formula. Euler subsequently returned to interpolation and formulated the theory of ...
when n=2~(r+1)-1,it can be expressed by geometric progression∑ni=0x~i=∏rj=0(1+x~(2~j)). 当n=2r+1 -1时,几何级数可以表示为:∑ni=0xi=∏rj=0(1+x2j)。 更多例句>> 3) geometric series 几何级数 例句>> 4) the product of geometric series 几何加权级数的乘积和 1. Consi...
We are tempted to use the formula we have found before. That is Tn=n(n+1)/2Tn=n(n+1)/2 which is equal to (n2+n)/2(n2+n)/2.Using the sigma notation one could write. ∑k=1nTk=1/2∑k=1nk(k+1)∑k=1nTk=1/2∑k=1nk(k+1)Thinking of these relations from a geometric ...