Write a Java program to print the sum (addition), multiply, subtract, divide and remainder of two numbers. Test Data: Input first number: 125 Input second number: 24 Pictorial Presentation: Sample Solution-1 Java Code: publicclassExercise6{publicstaticvoidmain(String[]args){// Create a Scanne...
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// In case your second argument is zero, you should print the "Division by 0!" message.
return sum; // Return the total sum of the numbers found in the string } // Main method to execute the program public static void main(String[] args) { Main m = new Main(); // Create an instance of the Main class String str1 = "it 15 is25 a 20string"; // Given input strin...
When num is equal to 0, there is no recursive call and this returns the sum of integers to the main() function. Here's the equivalent Java code: Java Program to Find Sum of Natural Numbers using RecursionShare on: Did you find this article helpful?Our...
The above program takes input from the user and stores it in the variable n. Then, for loop is used to calculate the sum up to n. Sum of Natural Numbers Using while Loop #include <stdio.h> int main() { int n, i, sum = 0; printf("Enter a positive integer: "); scanf("%d",...
//C# program to calculate the sum of binary numbers.usingSystem;classBinarySum{staticvoidCalculateBinarySum(intnum1,intnum2){inti=0;intrem=0;stringstr="";while(num1!=0|| num2!=0){str+=(num1%10+num2%10+rem)%2;rem=(num1%10+num2%10+rem)/2;num1=num1/10;num2=num2/10;}if(rem...
Program to find sum of all digits in java importjava.util.Scanner;publicclassAddDigits{publicstaticvoidmain(Stringargs[]){// initializing and declaring the objects.intnum,rem=0,sum=0,temp;Scanner scan=newScanner(System.in);// enter number here.System.out.print("Enter the Number : ");num...
This is a Java Program to Calculate the Sum of Odd & Even Numbers. Enter the number of elements you want in array. Now enter all the elements you want in that array. We begin from the first element and check if it is odd or even. Hence we add that number into the required addition...
Note that ⌊t√⌋⌊t⌋ always lies in the corner of the rectilinear convex hull of points below kl=tkl=t. There are two cases two consider here: The corner is "concave", that is ⌊t√⌋(⌊t√⌋+1)≤t⌊t⌋(⌊t⌋+1)≤t. It means that ⌊t√⌋=⌊t/l...