public static void main(String[]args){Scanner scanner=new Scanner(System.in);//Taking userinputSystem.out.print("Enter a number: ");intnumber=scanner.nextInt();//Calculatinganddisplaying thesumof digitsintsum=calculateSum(number);System.out.println("Sum of digits: "+sum);scanner.close();}...
Java Code: importjava.util.Scanner;publicclassExercise6{publicstaticvoidmain(String[]args){Scannerin=newScanner(System.in);System.out.print("Input an integer: ");intdigits=in.nextInt();System.out.println("The sum is "+sumDigits(digits));}publicstaticintsumDigits(longn){intresult=0;while(n...
import java.util.Scanner;public class N {public static int sumDigits(long n){int sum=0;while(n>0){int m=(int)(n%10);sum=sum+m;n=n/10;}return sum;}public static void main(String[] args) {try{System.out.println("请输入数字:");Scanner sc=new Scanner(System.in);long l=sc....
} System.out.print("Sum of digits of number "+tempNum+" is "+total); } } Output: Enter a Number : 5385 Sum of digits of number 5385 is 21 That’s all about Java program to add digits of number.
// Find sum and average of two numbers in Java import java.util.*; public class Numbers { public static void main(String args[]) { int a, b, sum; float avg; Scanner buf = new Scanner(System.in); System.out.print("Enter first number : "); a = buf.nextInt(); System.out....
Program to find sum of all digits in javaimport java.util.Scanner; public class AddDigits { public static void main(String args[]) { // initializing and declaring the objects. int num, rem=0, sum=0, temp; Scanner scan = new Scanner(System.in); // enter number here. System.out....
import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock; /** * * How to find sum of digits in Java * * @author Javin Paul */ public class SumOfDigits{ public static void main(String args[]) { Scanner sc = new...
Learn how to calculate the sum of all multiples of a given number using JavaScript. This tutorial provides step-by-step guidance and examples.
Given an integer number n, return the difference between the product of its digits and the sum of its digits. Example 1: Input: n = 234 Output: 15 Explanation: Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 15 ...
1099. Two Sum Less Than K解题方法先排序,然后调用二分查找函数获取比 k 小的第一个数的下标 end,设置 start = 0,当 start < end 时做循环,计算 nums[start] + nums[end] 的值 Sum,判断 Sum 和 k 的关系,如果 Sum >= k 就把 end 减1,否则 start + 1 后更新和的最大值 maxsum。循环结束后...