vector<int> sums;helper(root,1, sums);returndistance(begin(sums),max_element(begin(sums),end(sums))) +1; }voidhelper(TreeNode* node,intlevel, vector<int>& sums){if(!node)return;if(sums.size() < level) sums.resize(level); sums[level -1] += node->val;helper(node->left, level ...
https://github.com/grandyang/leetcode/issues/834 类似题目: Binary Tree Postorder Traversal Binary Tree Preorder Traversal Distribute Coins in Binary Tree 参考资料: https://leetcode.com/problems/sum-of-distances-in-tree/ https://leetcode.com/problems/sum-of-distances-in-tree/discuss/161975/My-D...
Find the number of paths that sum to a given value. The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes). The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to...
Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Example 1: AI检测代码解析 Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 ...
题目链接:Path Sum II | LeetCode OJ Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and sum = 22, 5 /\ 48 //\ 11134 /\/\ ...
13 -- 1:15 App Python小白刷LeetCode Day43 Contains duplicate 23 -- 2:01 App Python小白刷LeetCode Day63 Power of Four 1/9 8 -- 2:15 App Python小白刷LeetCode Day72 Ransom Note 13 -- 1:40 App Python小白刷LeetCode Day20 balanced binary tree 12/01 17 -- 3:18 App Python小...
方法2是Leetcode上的Solution,思路是先初始化了一个self.ans为0,然后逐个遍历节点,每遇到一个在[L,R]内的节点,就做一次加法累进self.ans。 具体的做法: 判断当前节点是否在[L,R]内,在的话self.ans加上当前节点值,不在的话继续步骤2和3 判断左子树是否可能存在符合要求的节点。根据二叉搜索树定义,左子树中...
Given a non-empty binary tree, find the maximum path sum. For this problem, a path is defined as any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The path must contain at least one node and does not need to go through the root...
【Binary Indexed Tree/树状数组】307. Range Sum Query - Mutable 3915 -- 9:29 App LeetCode 920. Number of Music Playlists 186 -- 10:33 App [English] LeetCode 233. Number of Digit One 399 -- 12:49 App LeetCode 1074. Number of Submatrices That Sum to Target 1329 8 10:24 App ...
# class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def rangeSumBST(self, root: Optional[TreeNode], low: int, high: int) -> int: # 如果 root 子树为空,则直接返回 0 if not root...