vector<int> sums;helper(root,1, sums);returndistance(begin(sums),max_element(begin(sums),end(sums))) +1; }voidhelper(TreeNode* node,intlevel, vector<int>& sums){if(!node)return;if(sums.size() < level) sums.resize(level); sums[level -1] += node->val;helper(node->left, level ...
https://github.com/grandyang/leetcode/issues/834 类似题目: Binary Tree Postorder Traversal Binary Tree Preorder Traversal Distribute Coins in Binary Tree 参考资料: https://leetcode.com/problems/sum-of-distances-in-tree/ https://leetcode.com/problems/sum-of-distances-in-tree/discuss/161975/My-D...
Find the number of paths that sum to a given value. The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes). The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to...
# class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def rangeSumBST(self, root: Optional[TreeNode], low: int, high: int) -> int: # 如果 root 子树为空,则直接返回 0 if not root...
[leetcode] 1302. Deepest Leaves Sum Description Given a binary tree, return the sum of values of its deepest leaves. Example 1: Input: root = [1,2,3,4,5,null,6,7,null,null,null,null,8] Output: 15 1. 2. Constraints: The number of nodes in the tree is between 1 and 10^4....
47 -- 2:48 App 你这题保熟吗 Leetcode 24. Swap Nodes in Pairs 15 -- 1:53 App 你这题保熟吗 Leetcode 104. Maximum Depth of Binary Tree 28 -- 2:07 App 你这题保熟吗 Leetcode 38 -- 4:09 App 你这题保熟吗 Leetcode 1696. Jump Game VI 友情...
题目链接:Path Sum II | LeetCode OJ Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum. For example: Given the below binary tree and sum = 22, 5 /\ 48 //\ 11134 /\/\ ...
【Binary Indexed Tree/树状数组】307. Range Sum Query - Mutable 3915 -- 9:29 App LeetCode 920. Number of Music Playlists 186 -- 10:33 App [English] LeetCode 233. Number of Digit One 399 -- 12:49 App LeetCode 1074. Number of Submatrices That Sum to Target 1329 8 10:24 App ...
方法2是Leetcode上的Solution,思路是先初始化了一个self.ans为0,然后逐个遍历节点,每遇到一个在[L,R]内的节点,就做一次加法累进self.ans。 具体的做法: 判断当前节点是否在[L,R]内,在的话self.ans加上当前节点值,不在的话继续步骤2和3 判断左子树是否可能存在符合要求的节点。根据二叉搜索树定义,左子树中...
The number of nodes in the tree is in the range [1, 100]. 0 <= Node.val <= 100 All the values in the tree are unique. Note: This question is the same as538 题目描述: 给定一个二叉搜索树 root (BST),请将它的每个节点的值替换成树中大于或者等于该节点值的所有节点值之和。