The product of three consecutive natural numbers is 336. The sum of these natural numbers is.相关知识点: 试题来源: 解析 21 The prime factorization of 336 is:336=24×3×7=(2×3)×7×23=6×7×8. The sum is then 21.反馈 收藏
The product of three consecutive natural numbers is 336. The sum of these natural numbers is . 相关知识点: 试题来源: 解析 21 The prime factorization of 336 is:336=24×3×7=(2×3)×7×23=6×7×8. The sum is then 21.反馈 收藏 ...
Learn how to find the sum of the first n natural numbers. See what the sum of all natural numbers is and how to find the sum of cubes of the first...
In remarkable books in Theoretical Physics and String Theory an indication appears that the sum of the natural numbers is equal to minus one divided by twelve. Over the Internet one can find a proof which uses, in an arbitrary manner, computations with non-convergent series. The site has had...
The sum of two natural numbers is 17,402. One of the two numbers is divisible by 10. If the units digit of that number is erased, the other number is obtained. What is the difference of these two numbers? D(A)10,272((B)11,700(C)13,362(D)14,238(E)15,426 相关知识点: 试...
Natural numbers 1 to 100 is a set of first 100 natural numbers, where 100 is the largest natural number and 1 is the smallest one. Learn how to find the sum of natural numbers from 1 to 100 using concepts, formula,s and examples.
结果1 题目 (2) The sum of two natural numbers is an odd number; they are (C(A) both odd numbers(B) both even numbers(C) one odd number and one even number(D)uncertain 相关知识点: 试题来源: 解析 答案见上 反馈 收藏
Program to calculate the sum of natural numbers in Kotlin packagecom.includehelp.basicimport java.util.*//Main Function entry Point of Programfunmain(args: Array<String>) {//Input Streamvalscanner = Scanner(System.`in`)//input integer numberprint("Enter Number : ")valnumber: Int = scanner...
解析 S=1+2+3+4++n S=1+2+3+4++nThis is an arithmetic series witha=1, d=1, n=n .S =2[2 a+ ( n-1 )d] S =2[2 * 1+ ( n-1 )* 1]S =2 ( 2+n-1 )(split)S &=n/2(n+1) \&=1/2 n(n+1)(split)反馈 收藏 ...
解析 S=1+2+3+4++n S=1+2+3+4++nThis is an arithmetic series witha=1, d=1, n=n .S =2[2 a+ ( n-1 )d] S =2[2 * 1+ ( n-1 )* 1]S =2 ( 2+n-1 )(split)S &=n/2(n+1) \&=1/2 n(n+1)(split)反馈 收藏 ...